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Gnesinka [82]
2 years ago
10

Physics Practice Help just need an explanation really not looking for an answer

Physics
2 answers:
agasfer [191]2 years ago
8 0

This question involves the concepts of the law of conservation of energy and kinetic energy.

The variables required for a computational model that predicts change in the energy of a falling object are "B.)Height, speed, mass".

According to the law of conservation of energy the change in energy can be given in the following form for a falling object:

Loss in Potential Energy = Gain in Kinetic Energy

mgh = \frac{1}{2}mv^2

It is clear from the formula that the variables involved in the computational model are <u>mass, height, and velocity</u>.

Learn more about the law of conservation of energy hee:

brainly.com/question/381281?referrer=searchResults

melamori03 [73]2 years ago
8 0

Answer:

b) height, speed, mass

Explanation:

just took the test

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How do I draw a four-cell battery with the cells connected in series with each other?
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Answer:

Explanation:

Arrangements of cells, when two or more cells are connected together they form what is called a battery

There are two ways cells can be connected

1. Parallel

2. Series

Find attached a sketch of serial arrangement

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3 years ago
An explanation for planetary differentiation is_____________.
Luda [366]

Answer:

C. The process through which distinct layers with characteristic chemical and/or physical properties are formed

Explanation:

I know It cause i took that test last year. Just wanna help GL.

5 0
3 years ago
n alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 5.94 cm in a uniform magnetic field with B = 1.10 T.
9966 [12]

Answer:

a). V = 3.13*10⁶ m/s

b). T = 1.19*10^-7s

c). K.E = 2.04*10⁵

d). V = 1.02*10⁵V

Explanation:

q = +2e

M = 4.0u

r = 5.94cm = 0.0594m

B = 1.10T

1u = 1.67 * 10^-27kg

M = 4.0 * 1.67*10^-27 = 6.68*10^-27kg

a). Centripetal force = magnetic force

Mv / r = qB

V = qBr / m

V = [(2 * 1.60*10^-19) * 1.10 * 0.0594] / 6.68*10^-27

V = 2.09088 * 10^-20 / 6.68 * 10^-27

V = 3.13*10⁶ m/s

b). Period of revolution.

T = 2Πr / v

T = (2*π*0.0594) / 3.13*10⁶

T = 1.19*10⁻⁷s

c). kinetic energy = ½mv²

K.E = ½ * 6.68*10^-27 * (3.13*10⁶)²

K.E = 3.27*10^-14J

1ev = 1.60*10^-19J

xeV = 3.27*10^-14J

X = 2.04*10⁵eV

K.E = 2.04*10⁵eV

d). K.E = qV

V = K / q

V = 2.04*10⁵ / (2eV).....2e-

V = 1.02*10⁵V

7 0
3 years ago
How does space promote science education
Fittoniya [83]
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3 0
3 years ago
please solve this for me ,A garden roller is pulled with a force of 200N acting at an angle of 50 degree with the ground level.f
Bingel [31]

Answer:

The force pulling the roller along the ground is 128.55 N

Explanation:

A force of 200 N acting at an angle of 50° with the ground level

This force is pulled a garden roller

We need to find the force pulling the roller along the ground

The force that pulling the roller along the ground is the horizontal

component of the force acting

→ The force acting is 200 N at direction 50° with ground (horizontal)

→ The horizontal component = F cosФ

→ F = 200 N , Ф = 50

→ The horizontal component = 200 cos(50) = 128.55 N

128.55 N is the horizontal component of the force that pulling the

roller along the ground

<em>The force pulling the roller along the ground is 128.55 N</em>

8 0
3 years ago
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