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2 years ago

Physics Practice Help just need an explanation really not looking for an answer

Physics

2 answers:

agasfer [191]2 years ago

8 0

This question involves the concepts of the law of conservation of energy and kinetic energy.

The variables required for a computational model that predicts change in the energy of a falling object are "B.)Height, speed, mass".

According to the law of conservation of energy the change in energy can be given in the following form for a falling object:

Loss in Potential Energy = Gain in Kinetic Energy

$mgh = \frac{1}{2}mv^2$

It is clear from the formula that the variables involved in the computational model are <u>mass, height, and velocity</u>.

Learn more about the law of conservation of energy hee:

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melamori03 [73]2 years ago

8 0

Answer:

b) height, speed, mass

Explanation:

just took the test

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J.J. Thomson discovered the electron by noticing that: A. molecules with the same atoms exhibited the same chemical properties.

GenaCL600 [577]

J.J. Thomson discovered the electron by noticing that a beam of particles could be influenced by an electric or magnetic force.. That is option B.

<h3>What is an electron?</h3>

An electron can be defined as the part of an atom that is negatively charged and is found revolving round the nucleus of an atom.

J.J. Thomson was the scientist that discovered electrons through subjecting two oppositely-charged electric plates around the cathode ray.

He noticed that the particles where deflected by both the magnetic and electric fields.

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4 0

2 years ago

The y-position of a damped oscillator as a function of time is shown in the figure.

NISA [10]

(1) The period of the oscillator is 1 second.

(2) The damping coefficient is 0.93.

<h3>What is period of oscillation?</h3>

The period of oscillation is the time taken to make one complete cycle.

From the graph, the time taken to make one complete oscillation is 1 second.

<h3>Damping coefficient</h3>

equation of the wave is given as;

y(t) = Ae^(-btx) cos(ωt)

3.5 = Ae^(-0) cos(0)

3.5 = A x 1

A = 3.5 cm

-3 = 3.5e^(-bx) cos(ω)

-3/3.5 = e^(-bx) cos(ω)

-0.857 = e^(-bx) cos(ω)

-0.857 / cos(ω) = e^(-bx)

ln[-0.857 / cos(ω)] = -bx

ln[-0.857 / cos(ω)] / b = - x ---- (1)

-2 = 3.5e^(-2bx) cos(2ω)

-0.57 = e^(-2bx) cos(2ω)

ln[-0.57 / cos(2ω)] = -2bx

ln[-0.57 / cos(2ω)] /2b = - x ------(2)

solve (1) and (2)

ln[-0.57 / cos(2ω)]/2b = ln[-0.857 / cos(ω)] /b

-0.57 / cos(ω) = 2(-0.857 / cos(ω))

2(-0.857/cosω) = -0.57/cos2ω

-(2 x 0.857) / (-0.57) = cosω/cos 2ω

3 = cosω/cos 2ω

3(cos 2ω) = cosω

3(2cos²ω - 1) = cos ω

6cos²ω - 6 = cosω

6cos²ω - cosω - 6 = 0

let cosω = y

6y² - y - 6 = 0

solve the quadratic equation;

y = 1.1 or -0.92

cosω = -0.92

ω = arc cos(-0.92)

ω = 2.74 rad/s

From equation (1)

ln[-0.857 / cos(ω)] / x = -b ---- (1)

let x = 1

ln(-0.857/cos(2.74) = -b

-0.93 = -b

b = 0.93

Thus, the damping coefficient is 0.93.

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4 0

2 years ago

IP The x and y components of a vector r⃗ are rx = 16 m and ry = -8.5 m , respectively

fiasKO [112]

as it is given that

$r_x = 16 m$

$r_y = -8.5 m$

now we will have

$\vec r = 16 \hat i - 8.5 \hat j$

now the magnitude of this vector is given as

$|r| = \sqrt{16^2 + 8.5^2}$

$|r| = 18 m$

now to find the direction we can use

$tan\theta = \frac{r_y}{r_x}$

$tan\theta = \frac{-8.5}{16}$

$\theta = tan^{-1}(-0.53)$

$\theta = - 28^0$

4 0

3 years ago

Question 1 of 25

finlep [7]

Answer:

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

<em>Hence the gravitational force between the asteroid is 2.753*10^-11N</em>

6 0

2 years ago

An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally

amid [387]

The tension in the supporting cable when the cab originally moves downward is 18422.4 N

What is tension?

Tension is described as the pulling force by the means of a three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

Here,

m =combined mass = 1600 kg

s = Displacement of the elevator = 42 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 12 m/s

v = Final velocity = 0

According to the equation of motion:

$v^{2} - u^{2} = 2as$

0 - 12^2 = 2*a*42

a = - 144 / 84

a = - 1.714 m/s^2

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

T-mg = ma

T = m(g-a)

T = 1600 ( 9.8-(-1.74))

T=18422.4 N

Hence,

The tension in the supporting cable when the cab, originally moving downward is 18422.4 N

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6 0

2 years ago