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Gnesinka [82]
2 years ago
10

Physics Practice Help just need an explanation really not looking for an answer

Physics
2 answers:
agasfer [191]2 years ago
8 0

This question involves the concepts of the law of conservation of energy and kinetic energy.

The variables required for a computational model that predicts change in the energy of a falling object are "B.)Height, speed, mass".

According to the law of conservation of energy the change in energy can be given in the following form for a falling object:

Loss in Potential Energy = Gain in Kinetic Energy

mgh = \frac{1}{2}mv^2

It is clear from the formula that the variables involved in the computational model are <u>mass, height, and velocity</u>.

Learn more about the law of conservation of energy hee:

brainly.com/question/381281?referrer=searchResults

melamori03 [73]2 years ago
8 0

Answer:

b) height, speed, mass

Explanation:

just took the test

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a layer of sandstone is in contact with a mass of granite. the sandstone contains small fragments of the granite. which rock is
lara31 [8.8K]
The granite would be older. As millions of years go by, rocks are affected by weathering and erosion. These processes break down rocks and scatter them. Rocks are broken down into sediments, which mix with other layers, which could have been the reason how the layer of sandstone contains the small fragments of granite.
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3 years ago
A swinging pendulum has a total energy of <img src="https://tex.z-dn.net/?f=E_i" id="TexFormula1" title="E_i" alt="E_i" align="a
Zolol [24]

Answer:

\frac{E_{2}}{E_{1}} \approx 1 -\frac{3\theta}{1-\theta} (for small oscillations)

Explanation:

The total energy of the pendulum is equal to:

E_{1} = m\cdot g \cdot (1-\cos \theta)\cdot L

For small oscillations, the equation can be re-arranged into the following form:

E_{1} \approx m\cdot g \cdot (1-\theta) \cdot L

Where:

\theta = \frac{A}{L^{2}}, measured in radians.

If the amplitude of pendulum oscillations is increase by a factor of 4, the angle of oscillation is 4\theta and the total energy of the pendulum is:

E_{2} \approx m\cdot g \cdot (1-4\theta)\cdot L

The factor of change is:

\frac{E_{2}}{E_{1}} \approx \frac{1 - 4\theta}{1-\theta}

\frac{E_{2}}{E_{1}} \approx 1 -\frac{3\theta}{1-\theta}

3 0
3 years ago
Estimate how long a 2500 W electric kettle would take to boil away 1.5 Kg of water . The specific latent heat of vaporization of
andrew-mc [135]

The time it would take a 2500 W electric kettle to boil away 1.5 Kg of water is 2400 seconds

<h3>How to calculate the time</h3>

Use the formula:

Power × time = mass × specific heat

Given mass = 1. 5kg

Specific latent heat of vaporization = 4000000 J/ Kg

Power = 2500 W

Substitute the values into the formula

Power × time = mass × specific heat

2500 × time = 1. 5 × 4000000

Make 'time' the subject

time = 1. 5 × 4000000 ÷ 2500 = 6000000 ÷ 2500 = 2400 seconds

Therefore, the time it would take a 2500 W electric kettle to boil away 1.5 Kg of water is 2400 seconds.

Learn more about specific latent heat of vaporization:

https://brainly.in/question/1580957

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8 0
2 years ago
Two long straight wires are parallel and 8.6 cm apart. They are to carry equal currents such that the magnetic field at a point
Neko [114]

Answer:

(a) The current should be in opposite direction

(b) The current needed is 39.8 A

Explanation:

Part (a)

Based, on right hand rule, the current should be in opposite direction

Part (b)

given;

strength of magnetic field, B = 370 µT

distance between the two parallel wires, d = 8.6 cm

B = \frac{\mu_oI}{2\pi R}

At the center, the magnetic field strength is twice

B_c = 2(\frac{\mu_oI}{2\pi R}) =\frac{ \mu_oI}{\pi R}

R = d/2 = 8.6/2 = 4.3 cm = 0.043 m

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Therefore, current needed is 39.8 A

6 0
3 years ago
How does the matter and (solar) energy move through the sphere?
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When the Sun's energy moves through space, it reaches Earth's atmosphere and finally the surface. This radiant solar energy warms the atmosphere and becomes heat energy. This heat energy is transferred throughout the planet's systems in three ways: by radiation, conduction, and convection.
5 0
3 years ago
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