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1 year ago

Physics Practice Help just need an explanation really not looking for an answer

Physics

2 answers:

agasfer [191]1 year ago

8 0

This question involves the concepts of the law of conservation of energy and kinetic energy.

The variables required for a computational model that predicts change in the energy of a falling object are "B.)Height, speed, mass".

According to the law of conservation of energy the change in energy can be given in the following form for a falling object:

Loss in Potential Energy = Gain in Kinetic Energy

$mgh = \frac{1}{2}mv^2$

It is clear from the formula that the variables involved in the computational model are mass, height, and velocity.

Learn more about the law of conservation of energy hee:

brainly.com/question/381281?referrer=searchResults

melamori03 [73]1 year ago

8 0

Answer:

b) height, speed, mass

Explanation:

just took the test

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A projectile is fired at v 0 = 381.0 m/s at an angle of θ = 73.5 ∘ , with respect to the horizontal. Assume that air friction wi

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Answer:

Explanation:

velocity of projection, vo = 381 m/s

angle of projection, θ = 73.5°

The formula for the range is

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3 years ago

What is the electric potential v due to the nucleus of hydrogen at a distance of 5.292×10−11 m ?

viktelen [127]

Answer: 27.21 V

Explanation:

The electric potential $V_{E}$ due to a point charge is expressed as:

$V_{E}=k\frac{q}{r}$

Where:

$k=9(10)^{9}\frac{Nm^{2}}{C^{2}}$ is the electric constant

$q=1.6(10)^{-19}C$ is the electric charge of the hydrogen nucleus, which is positive

$r=5.292(10)^{-11}m$ is the distance

Rewritting the equation with the known values:

$V_{E}=9(10)^{9}\frac{Nm^{2}}{C^{2}}\frac{1.6(10)^{-19}C}{5.292(10)^{-11}m}$

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3 years ago

In a Little League baseball game, the 145 g ball enters the strike zone with a speed of 17.0 m/s . The batter hits the ball, and

VMariaS [17]

Hi there!

Impulse = Change in momentum

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Where:

m = mass of object (kg)

vf = final velocity (m/s)

vi = initial velocity (m/s)

Begin by converting grams to kilograms:

1 kg = 1000g ⇒ 145g = .145kg

Now, plug in the given values. Remember to assign directions since velocity is a vector. Let the initial direction be positive and the opposite be negative.

I = (.145)(-20 - 17) = -5.365 Ns

The magnitude is the absolute value, so:

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1 year ago