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valentinak56 [21]
4 years ago
15

Now, consider the resultant electric field e⃗ net at p. with reference to the coordinate system shown in the previous part, whic

h component of e⃗ net, if any, is zero in this problem?
Physics
1 answer:
Rzqust [24]4 years ago
5 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices:
only the x component
only the y component
both the x and y components
neither the x nor the y component

The answer is neither the x nor the y component

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Can someone pls help me with this?
alexira [117]
C because they are both going in a constant speed
6 0
3 years ago
If a box weighing 520 N is hung from a spring whose constant is 650 N/m, how many centimeters will the spring stretch?
lara [203]

80 cm

hope this helps :)

3 0
3 years ago
Read 2 more answers
1. How long is a day on Venus?
KIM [24]

Answer:

2:Venus is often named as Earth's twin because both worlds share a similar size, surface composition and have an atmosphere with a complex weather system. ... Both planets have almost the same size and density and Venus is only a 30% closer to the Sun than Earth 1:116d 18h 0m 3: The atmosphere of Venus is made up almost completely of carbon dioxide. It also includes small doses of nitrogen and clouds of sulfuric acid. ... This composition causes a runaway greenhouse effect that heats the planet even hotter than the surface of Mercury, although Venus lies farther from the sun.

Explanation:

7 0
3 years ago
A 2000-kg car moving with a speed of 20 m/s collides with and sticks to a 1500-kg car at rest at a stop sign. Show that because
amid [387]

Answer:

13.33m/s

Explanation:

Given data

m1= 2000kg

u1= 20m/s

m2= 1500kg

u2= 0m/s

v1= 10m/s

Required

The speed of the sticks

We know that  from the expression for the conservation of momentum

m1u1+m2u2= m1v1+m2v2

2000*20+1500*0=2000*10+1500*v2

40000=20000+1500v2

collect like terms

40000-20000= 1500v2

20000= 1500v2

v2= 20000/1500

v2= 13.33 m/s

Hence the velocity of the sticks is 13.33m/s

8 0
3 years ago
A 200 g block is pressed against a spring of force constant 1.40 kN/m until the block compresses the spring 10.0 cm. The spring
tino4ka555 [31]

Answer:

Explanation:

This problem bothers on the energy stored in a spring in relation to conservation of energy

Given data

Mass of block m =200g

To kg= 200/1000= 0.2kg

Spring constant k = 1.4kN/m

=1400N/m

Compression x= 10cm

In meter x=10/100 = 0.1m

Using energy considerations or energy conservation principles

The potential energy stored in the spring equals the kinetic energy with which the block move away from the spring

Potential Energy stored in spring

P.E=1/2kx^2

Kinetic energy of the block

K.E =1/mv^2

Where v = velocity of the block

K.E=P.E (energy consideration)

1/2kx^2=1/mv^2

Kx^2= mv^2

Solving for v we have

v^2= (kx^2)/m

v^2= (1400*0.1^2)/0.2

v^2= (14)/0.2

v^2= 70

v= √70

v= 8.36m/s

a. Distance moved if the ramp exerts no force on the block

Is

S= v^2/2gsinθ

Assuming g= 9. 81m/s^2

S= (8.36)^2/2*9.81*sin60

S= 69.88/19.62*0.866

S= 69.88/16.99

S= 4.11m

6 0
3 years ago
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