Simplify each expression (e^2)(g)(g^4)(e^3) (e)(e^2)(e)

Mathematics

1 answer:

wolverine [178]2 years ago

7 0

9514 1404 393

Answer:

e^5g^5
e^4

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)(a^c) = a^(b+c)

$(e^2)(g)(g^4)(e^3)=e^{(2+3)}g^{(1+4)}=\boxed{e^5g^5}\\\\(e)(e^2)(e)=e^{(1+2+1)}=\boxed{e^4}$

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What is an equation of the line that passes through the point (-5,3)(−5,3) and is parallel to the line 3x-5y=303x−5y=30?

rosijanka [135]

The equation of the line which passes through the point (-5, 3) and is parallel to the equation 3x -5y = 30 is; 3x -5y = 30.

<h3>What is the equation of the line?</h3>

Since the line is parallel to the given line; 3x -5y = 30 whose slope is; 3/5.

Hence, since the two lines have equal slopes;

3/5 = (y-3)/(x-(-5))

3/5 = (y-3)/(x+5)

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If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"

seraphim [82]

Answer:

$a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b)$

Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$