Answer:
P = 9622.9 Pa = 9.62 KPa
Explanation:
First, we will calculate the mass of all three liquids:
m = ρV
where,
m = mass of liquid
ρ = density of liquid
V = Volume of liquid
FOR LIQUID 1:
m₁ = (2.8 x 10³ kg/m³)(2 x 10⁻³ m³) = 5.6 kg
m₂ = (1 x 10³ kg/m³)(1.5 x 10⁻³ m³) = 1.5 kg
m₃ = (0.6 x 10³ kg/m³)(1 x 10⁻³ m³) = 0.6 kg
The total mass will be:
m = m₁ + m₂+ m₃ = 5.6 kg + 1.5 kg + 0.6 kg
m = 7.7 kg
Hence, the weight of the liquids will be:
W = mg = (7.7 kg)(9.81 m/s²) = 75.54 N
Now, we calculate the base area:
A = πr² = π(0.05 m)²
A = 7.85 x 10⁻³ m²
Now the pressure will be given as:

<u>P = 9622.9 Pa = 9.62 KPa</u>
I think its ethylene, tell me if i'm wrong
Answer:
0.0170m or 1.70cm
Explanation:
L=(μ₀*N^2*A)/(l)
N=x/2*pi*r so r=x/2*pi*N
A=pi*r^2=(pi*x^2)/(4*pi^2*N^2)
L=(μ₀*N^2*A)/(l)=(μ₀*N^2*pi*x^2)/(4*pi^2*N^2*l)=(μ₀*x^2)/(4*pi*l)
l=(μ₀*x^2)/4*pi*L)=[(4*10^-7)*(1.15m)/4*pi*2.47*10^-6H)=0.0170m or 1.70cm
Hope this helps. Any questions please feel free to ask. Thanks!
Answer: The force acting on the proton of charge 1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.
Explanation: To find the answer we need to know more about the Lorentz magnetic force.
<h3>What is the Lorentz magnetic force acting on the proton?</h3>
- Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,
F= q (v× B)
where,
is the angle between v and B.
- In the question, it is given that,
because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.
- Thus, we can find the force acting on the proton as,

Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.
Learn more about the Lorentz magnetic force here:
brainly.com/question/28047923
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