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oksian1 [2.3K]
3 years ago
7

PLEASE HELP!! DUE SOON!! THANKS BRAINLIEST OFFERED!!

Physics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

real, inverted, and smaller than the object

Explanation:

When the object is placed beyond the center of curvature, the image will formed between the focus and the center of curvature. The size of the image is diminished and its nature is real and inverted.

The whole description is shown in the attached figure. It is clear that the size of the image is smaller than the object.

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Streams carry sediment, like pebbles, in their flows. The pebbles can be in a variety of locations in the flow, depending on it's size, the balance between the upwards velocity on the pebble (drag and lift forces), and it's settling velocity.
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3 years ago
Car A (1750 kg) is travelling due south and car B (1450 kg) is travelling due east. They reach the same intersection at the same
Contact [7]

Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as

\underset{V_{A}}{\rightarrow} = velocity of car A before collision = 0 i - V_{A} j

\underset{V_{B}}{\rightarrow} = velocity of car B before collision = V_{B} i + 0 j

\underset{V_{AB}}{\rightarrow} = velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j

M_{A} = mass of car A = 1750 kg

M_{B} = mass of car B = 1450 kg

Using conservation of momentum

M_{A}  \underset{V_{A}}{\rightarrow} + M_{B}  \underset{V_{B}}{\rightarrow} = (M_{A} + M_{B}) ( \underset{V_{AB}}{\rightarrow} )

(1750) (0 i - V_{A} j) + (1450) (V_{B} i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)

(1450) V_{B} i - (1750) V_{A} j = 97600 i - 60160 j

Comparing the coefficient of "i" and "j" both side

(1450) V_{B} = 97600    and - (1750) V_{A} = - 60160

V_{B} = 67.3 km/h        and  V_{A} = 34.4 km/



6 0
3 years ago
Give an example of a genotype for a person with brown hair. (brown is dominant)
nirvana33 [79]

Answer:

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Explanation:

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8 0
3 years ago
If you place two magnetic trains very close to eachother on a track will they atracct?​
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Explanation:

7 0
3 years ago
A 0.51-kg metal sphere oscillates at the end of a vertical spring. As the spring stretches from 0.12 m to 0.23 m (relative to it
den301095 [7]

Answer:

487.23 N/m

Explanation:

Given:

mass of metal sphere 'm'= 0.51kg

the spring stretches from 0.12 m to 0.23 m. Therefore,

s_1}= 0.12m and s_{2}= 0.23m

the speed of the sphere decreases from 6.7 to 3.3 m/s. Therefore,

v_{1}= 6.7m/s and v_2}=3.3m/s

In order to find spring constant, we apply law of conservation of energy. i.e

The change of the kinetic energy of sphere is equal to the change of potential energy of the spring.

So, ΔE_{k} = ΔE_{v}

where,

ΔE_{k} = 1/2 m (v_{1}- v_2})²

ΔE_{v}= 1/2 k (s_1} - s_{2})²

1/2 m (v_{1}- v_2})² = 1/2 k (s_{2}- s_1} )²

k= m [ (v_{1}- v_2})²/(s_{2}- s_1} )²

k= 0.51 [(6.7-3.3)²/ (0.23-0.12)²]

k= 487.23 N/m

Thus, the spring constant of the spring is 487.23 N/m

5 0
3 years ago
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