Answer:
m = 9795.9 kg
Explanation:
v = 35 m/s
KE = 6,000,000 J
Plug those values into the following equation:
6,000,000 J = (1/2)(35^2)m
---> m = 9795.9 kg
It behaves more like a metal
Explanation:
When an element tends to lose its valence electrons in chemical reactions, they behave more like a metal.
Metals are electropositive.
Electropositivity or metallicity is the a measure of the tendency of atoms of an element to lose electrons.
This is closely related to ionization energy and the electronegativity of the element.
- The lower the ionization energy of an element, the more electropositive or metallic the element is .
Metals are usually large size and prefers to be in reactions where they can easily lose their valence electrons.
When most metals lose their valence electrons, they attain stability.
Non-metals are electronegative. They prefer to gain electrons.
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My Physics teacher keeps giving us way too much work to do at home.
Answer:
emf will also be 10 times less as compared to when it has fallen 
Explanation:
We know, from faraday's law-
and 
So, as the height increases the velocity with which it will cross the ring will also increase. 
Given
Now, from 
From equation a and b we see that velocity when dropped from is 10 times greater when height is 40 
so, emf will also be 10 times less as compared to when it has fallen
Ok so here is the thing. It is necessary to introduce the atomic number Z into the following equation and the reason for that is that we are not working here with hydrogen (H). It will go like this:
<span>E=(2.18×10^-18 J)(Z^2 )|1/(ni^2 )-1/(nf^2 )| </span>
<span>E=(2.18×10^-18 J)(2^2 )|1/(6 ^2 )-1/(4 ^2 )|=3.02798×10^-19 J </span>
<span>After that we need to plug the E value calculated into the equation. Remember that the wavelength is always positive:</span>
<span>E=hc/λ 3.02798×10^-19 J=hc/λ λ=6.56×10^-7 m </span>
so 6.56×10^-7 m or better written 656 nm is in the visible spectrum
