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4 years ago

The supersonic airliner Concorde is 62.1 m long when sittingon

Physics

1 answer:

larisa86 [58]4 years ago

6 0

Answer:

$182.74020\ ^{\circ}C$

Explanation:

L = Initial length = 62.1 m

$\alpha$ = Coefficient of linear expansion of Aluminium = $24\times 10^{-6}/^{\circ}$

$T_i$ = Initial temperature = 15°C

$T_f$ = Final temperature

$\Delta L$ = Change in length = 25 cm

Change in length due to heat is given by

$\Delta L=L\alpha \Delta T\\\Rightarrow\Delta L=L\alpha (T_f-T_i)\\\Rightarrow T_f=\dfrac{\Delta L}{L\alpha}+T_i\\\Rightarrow T_f=\dfrac{0.25}{62.1\times 24\times 10^{-6}}+15\\\Rightarrow T_f=182.74020\ ^{\circ}C$

The temperature of the Concorde's skin in flight is $182.74020\ ^{\circ}C$

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Exercises

Crank

$\\ \rm\Rrightarrow \dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}$

$\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{1}{-10}+\dfrac{1}{38}$

$\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-19+5}{190}$

$\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-14}{190}$

$\\ \rm\Rrightarrow u=\dfrac{190}{-14}$

$\\ \rm\Rrightarrow u=13.6cm$

Real

5 0

3 years ago

If a farsighted person has a near point that is 0.600 mm from the eye, what is the focal length f2f2f_2 of the contact lenses th

Readme [11.4K]

Answer:

0.22mm

Explanation:

A far sighted person is a person suffering from long sightedness i.e such individual can only see far distant object clearly but not near distant object. The defect is corrected using convex lens.

Since convex lens is used, the focal (f) length of the lens is positive and the image distance (v) is also positive.

Using the lens formula,

1/f = 1/u + 1/v

Where u is the object distance = 0.35mm

v = 0.6mm

1/f = 1/0.35+1/0.6

1/f = 2.86 + 1.67

1/f = 4.53

f = 1/4.53

f = 0.22mm

The focal length of the contact lenses will be 0.22mm

5 0