ANSWER ASAP

Carmen is helping load furniture and boxes onto a moving truck. She

drek231 [11]

I think it’s contact I’m not sure

7 0

3 years ago

The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia is 64,900,000 . Determine th

Luba_88 [7]

Here is the complete question

The internal shear force V at a certain section of a steel beam is 80 kN, and the moment of inertia is 64,900,000 . Determine the horizontal shear stress at point H, which is located L = 20 mm below the centriod

The missing image which is the remaining part of this question is attached in the image below.

Answer:

The horizontal shear stress at point H is $\mathbf{\tau_H \approx 42.604 \ N/mm^2}$

Explanation:

Given that :

The internal shear force V = 80 kN = 80 × 10³ N

The moment of inertia = 64,900,000

The length = 20 mm below the centriod

The horizontal shear stress $\tau$ can be calculated by using the equation:

$\tau = \dfrac{VQ}{Ib}$

where;

Q = moment of area above or below the point H

b = thickness of the beam = 10 mm

From the centroid ;

Q = $Q_1 + Q_{2}$

Q = $A_1y_1 + A_{2}y_{2}$

Q = ( ( 70 × 10) × (55) + ( 210 × 15) (90 + 15/2) ) mm³

Q = ( ( 700) × (55) + ( 3150 ) ( 97.5) ) mm³

Q = ( 38500 + 307125 ) mm³

Q = 345625 mm³

$\tau_H = \dfrac{VQ}{Ib}$

$\tau_H = \dfrac{80*10^3 * 345625}{64900000*10 }$

$\tau_H = \dfrac{2.765*10^{10}}{649000000 }$

$\tau_H = 42.60400616 \ N/mm^2$

$\mathbf{\tau_H \approx 42.604 \ N/mm^2}$

The horizontal shear stress at point H is $\mathbf{\tau_H \approx 42.604 \ N/mm^2}$

7 0

3 years ago

Do tidal waves have the properties of a transverse wave, longitudinal wave, or both? ωΟω

solniwko [45]

Answer:

what im in faze clan faze up

Explanation:

4 0

3 years ago

A 8.3 resistor and a 5.4 resistor are connected in series with an emf source. The potential difference across the 5.4 resistor i

WINSTONCH [101]

Answer:

The potential difference across the source is 30.45 V.

Explanation:

In this setup we have a voltage divider, we were given the voltage difference on one of the resistors, we know that the difference pottential from the source in this case is the sum of the voltage in each individual resistor, so we can use the following equation to solve this problem:

V_resistor5.4 = (V_source)*(R_5.4)/(R_5.4+R_8.3)

V_source = (V_resistor5.4)*(R_5.4+R_8.3)/(R_5.4)

V_source = (12)*(5.4+8.3)/5.4

V_source = (12)*(13.7)/5.4 = 30.45 V

he potential difference across the source is 30.45 V.

6 0

3 years ago

New attempt is in progress. Some of the new entries may impact the last attempt grading. Incorrect. The hammer throw is a track-

Morgarella [4.7K]

This question involves the concepts of centripetal force, range of projectile and projectile motion.

The magnitude of centripetal force is "2812.8 N".

First, we will find the velocity of the ball by using the formula of the range of the projectile.