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tankabanditka [31]
3 years ago
12

When a person jumps up he or she is able to come down because of what?​

Physics
2 answers:
Ainat [17]3 years ago
7 0

Answer:

<h2>due to gravity........hope its helpful </h2>
Pani-rosa [81]3 years ago
3 0

Answer:

when a person jumps up he or she is able to come down because of the force of gravitation which pulls it back towards the Earth.

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Could dark matter be a higher dimensional object? Why?
REY [17]
Well dark matter is , in a layman terms just a concept used to identify missing mass in the universe. (extremely simplified and probably wrong but look that up). It could be but then if it is then we would still be able to percive the matter in some form. All we know from instruments is that they have mass and absorb light. We would need more info before any conclusions but it is 100% a possibility. But remember that when someone says "3-d" for example they are talking about a certain space.. technically matter exists on all planes (at least all the planes we know of in our local universe.) The laws of the cosmos are not yet proven to be constant and even if they are what of outside it?

When you take high school physics ask your teacher.
3 0
2 years ago
PLEASE HELP MEEE!!!
IRINA_888 [86]

Answer:

Option C

Explanation:

Answer C is the correct option. water can be written as H₂O, which means that there are 2 Hydrogen atoms for every oxygen atom,  therefore it will occupy more space than oxygen and push more. there is also one more possibility, if the splitting takes place in Hoffman's Voltameter then the Hydrogen will be close to the cathode as hydrogen is positive. Otherwise, option C is correct answer. Hope this Helps you!

4 0
3 years ago
A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How man
Ne4ueva [31]

Answer:  

A. α = - 1.047 rad/s²  

B. θ = 14.1 rad  

C. θ = 2.24 rev  

Explanation:  

A.  

We can use the first equation of motion to find the acceleration:

\omega_f = \omega_i + \alpha t  

where,  

ωf = final angular speed = 0 rad/s  

ωi = initial angular speed = (30 rpm)(2π rad/1 rev)(1 min/60 s) = 3.14 rad/s  

t = time = 3 s  

α = angular acceleration = ?  

Therefore,

0\ rad/s = 3.14\ rad/s + \alpha(3\ s)  

<u>α = - 1.047 rad/s²</u>

B.  

We can use the second equation of motion to find the angular distance:

\theta = \omega_it +\frac{1}{2}\alpha t^2\\\theta = (3.14\ rad/s)(3\ s) + \frac{1}{2}(1.04\ rad/s^2)(3)^2  

<u>θ = 14.1 rad</u>

C.  

θ = (14.1 rad)(1 rev/2π rad)  

<u>θ = 2.24 rev</u>

6 0
3 years ago
Whenever a net force acts on an object, there is a change in the object's _______?
Ksenya-84 [330]
Whenever a net force acts on an object, it means object is under acceleration which implies that there is change in the object's velocity.
4 0
3 years ago
-2 4/5 = -3 1/2n help pls
e-lub [12.9K]

Answer:

hello the correct answer is

Explanation:

n 4

--

5

4 0
2 years ago
Read 2 more answers
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