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Vera_Pavlovna [14]
3 years ago
7

Which reading strategy helps you to read and understand a passage quickly by making use of your previous knowledge?

Physics
1 answer:
Molodets [167]3 years ago
4 0
Taking notes,because you can read back on what you learned
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_ Ba+_O2 =_BaO how do I balance this?
astraxan [27]

Answer:

02-ba=_4

Explanation:

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3 years ago
Which equations could be used as is, or rearranged to calculate for frequency of a wave? Check all that apply.
gregori [183]
First one second one and last one
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4 years ago
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In a level parking lot, a man with a mass of 100 kg gives a shove to a boy with a mass of 50 kg who is on roller skates. The boy
natita [175]

Answer:

100N

Explanation:

Newton's third law states that whenever an object exerts a force on a second object, it exerts a force of equal magnitude and direction but in the opposite direction on the first. It is often stated as follows: Each action always opposes an equal but opposite reaction.

The subject 1 of 100kg is making a force F, to move an object from 50Kg to 2m / s ^ 2. This Force the object of 50Kg will reflect it in the opposite direction by Newton's third law.

Once the parameter of the force that both are experiencing is clarified, Newton's second law is applied to their respective calculation.

F = ma = 50kg * 2m / s ^ 2 = 100N

That is the force the boy exert on the man during the shove.

4 0
3 years ago
How is a conducter different from an insulater
Maru [420]

Answer:

Conductors have magnetic fields; insulators do not have magnetic fields. Conductors do not have magnetic fields; insulators do have magnetic fields. ... In a conductor, electric current cannot flow freely; in an insulator, it can flow freely.

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A rock is being twirled in a circle on the end of a string. The string provides the centripetal force needed to keep the ball mo
KonstantinChe [14]

Answer:

No

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The force of tension exerted by the string on the rock acts as centripetal force, so its direction is always towards the centre of the circle.

However, the direction of motion of the rock is always tangential to the circle: this means that the force is always perpendicular to the direction of motion of the rock.

As we know, the work done by a force on an object is

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the force and the displacement

In this situation, F and d are perpendicular, so \theta=90^{\circ}, therefore cos \theta = 0 and the work done is zero:

W=0

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3 years ago
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