All categories

3 years ago

How many moles are present in 454 grams of CO2?

Chemistry

2 answers:

inysia [295]3 years ago

5 0

Answer: The correct answer is Option A.

Explanation:

To calculate the number of moles, we use the formula given by the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Where,

Given mass of $CO_2$ = 454 grams

Molar mass of $CO_2=[12+(2\times 16)]=44g/mol$

Putting values in above equation, we get:

$\text{Moles of }CO_2=\frac{454g}{44g/mol}=10.31mol$

Hence, the correct answer is Option A.

Liula [17]3 years ago

4 0

A. 454 ÷ 44 =10.318181818182 = 10.31 Ans

You might be interested in

I'LL MARK U BRAINLIEST-How many kW does a nuclear power plant use in a year?

Lisa [10]

Answer:

Nuclear power comes from nuclear fission

Nuclear power plants use heat produced during nuclear fission to heat water. In nuclear fission, atoms are split apart to form smaller atoms, releasing energy. Fission takes place inside the reactor of a nuclear power plan

Explanation:

8 0

3 years ago

How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif

Katena32 [7]

Answer: The number of moles of strontium bicarbonate is $7.5\times 10^{-9}mol$

Explanation:

Formula units are defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is $6.022\times 10^{23}$

We are given:

Number of formula units of $Sr(HCO_3)_2=4.55\times 10^{15}$

As, $6.022\times 10^{23}$ number of formula units are contained in 1 mole of a substance.

So, $4.55\times 10^{15}$ number of formula units will be contained in = $\frac{1}{6.022\times 10^{23}}\times 4.55\times 10^{15}=7.5\times 10^{-9}mol$ of strontium bicarbonate.

Hence, the number of moles of strontium bicarbonate is $7.5\times 10^{-9}mol$

5 0

3 years ago

Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta

shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]$

Putting the values we get :

$\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]$

$\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]$

$\Delta H=-5314.8kJ$

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = $\frac{5314.8}{2}\times 1=2657.4kJ$

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0

3 years ago

A molecular covalent substance (such as co2) has a low melting point because the covalent bonds that hold the molecules together

Leona [35]

A molecular covalent substance (such as co2) has a low melting point because the covalent bonds that hold the molecules together are weak and do not require much energy to break:- False.

What are covalent bonds ?

An electron transfer that leads to the formation of electron pairs between atoms is known as a covalent bond. When atoms share electrons, a stable balance of the repulsive and attractive forces among them is known as covalent bonding. These electron pairs are also known as bonds or shared pairs.

It is a molecular compound, which is a mixture of at least two atoms—the smallest building blocks of matter—joined by a covalent bond. These atoms are joined by a covalent bond, which is formed when electrons are shared.

Learn more about covalent bond here:-

brainly.com/question/19382448

#SPJ4

6 0

2 years ago

What volume of a 6.67 M NaCl solution contains 3.12 mol NaCl? L

harkovskaia [24]

Answer:

0.47dm³

Explanation

Given parameters :

Molarity of NaCl = 6.67M

Number of moles = 3.12mol

Volume of NaCl =?

Volume of NaCl = number of moles/Molarity

Volume of NaCl = 3.12mol/6.67M

Volume of NaCl = 0.47dm³

4 0

4 years ago

Read 2 more answers