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malfutka [58]
2 years ago
15

Calculate the volume which 1.00 mole of a gas occupies at 1 atm and 298K?

Chemistry
1 answer:
elena-14-01-66 [18.8K]2 years ago
7 0

Answer:

25.45 Liters

Explanation:

Using Ideal Gas Law PV = nRT => V = nRT/P

V = (1mole)(0.08206Latm/molK)(298K)/(1atm) = 25.45 Liters

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The average atomic weight = 121.7598 amu

Explanation:

The average atomic weight of natural occurring antimony can be calculated as follows :

To calculate the average atomic mass the percentage abundance must be converted to decimal.

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The final step is adding the value to get the average atomic weight.

69.169178400 + 52.590621600 = 121.7598 amu

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