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Paul [167]
3 years ago
15

If the spin of one electron in an orbital is clockwise, what is the spin of the other electron in that orbital?

Chemistry
1 answer:
umka2103 [35]3 years ago
3 0

Answer:

The other electron must have anticlockwise spin.

Explanation:

According to the pauli exclusion principle, the two elecrton present in same orbital must have opposite spin.

If the one electron is clockwise the other must be in anti clockwise direction. The clockwise direction is represented by the sign +1/2 while anti clockwise direction is represented by -1/2.

According the pauli principle, the two electrons must have different fourth electronic quantum number. The electron in same orbital have same first three quantum number i.e, n=1 l=0 and ml =0 in case of first subshell.

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Which salt is formed by the reaction between hydrochloric acid and sodium hydroxide, write with chemical equation. .​
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Answer:

salt sodium chloride (NaCl)

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3 years ago
What is the wavelength (in nm) of the least energetic spectral line in the visible series of the H atom?
grin007 [14]

Answer:

Brackett Series (n = 4)

Explanation:

The least energetic line of Hydrogen atom lies in <em>Brackett Series </em>when n = 4 because these are least energetic, have longer wavelengths and lies in Infrared region of spectrum.  No traces of <em>Pfund series </em>are formed by H=atoms.

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Is aloe vera a living or non-living thing?
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Answer:

It is a living plant

Explanation:

3 0
3 years ago
Complete the reaction, which is part of the electron transport chain. The abbreviation FMN represents flavin mononucleotide. Use
Margarita [4]

Answer:

1. NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂

2. The reactant that is reduced is Q

3. The charge on iron on the right side is +2, Fe²⁺

Explanation:

NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂

The reaction above is catalysed by NADH:ubiquinone oxidoreductase (complex 1), which transfers a hydride ion from NADH to FMN, from which two electrons pass through a series of of Fe-S centers to the iron-sulfur protein N-2. Electron transfer from N-2 to Ubiquinone forms QH₂

The species in a reaction which gains hydrogen irons is reduced,   Therefore, the reactant that is reduced is Q, ubiquinone to form QH₂, ubiquinol.

To determine the oxidation number of iron on the right side of the reaction below,

QH2 + 2cyt c ( Fe3+) ⟶ Q + 2cyt c(Fex) + 2H^+

Sum of charges on the left side = Sum of charges on the right side

Sum of charges on the left side = 2 *+3 = +6

Therefore 2 * x + 2= 6

2x = 6 -2 = 4

x = 4/

x = 2

Therefore the charge on iron on the right side is +2, Fe²⁺

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3 years ago
What does changing densities cause to occur
Dafna1 [17]

Answer:

Explanation:

Please Elaborate

8 0
3 years ago
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