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3 years ago

If the spin of one electron in an orbital is clockwise, what is the spin of the other electron in that orbital?

Chemistry

1 answer:

umka2103 [35]3 years ago

3 0

Answer:

The other electron must have anticlockwise spin.

Explanation:

According to the pauli exclusion principle, the two elecrton present in same orbital must have opposite spin.

If the one electron is clockwise the other must be in anti clockwise direction. The clockwise direction is represented by the sign +1/2 while anti clockwise direction is represented by -1/2.

According the pauli principle, the two electrons must have different fourth electronic quantum number. The electron in same orbital have same first three quantum number i.e, n=1 l=0 and ml =0 in case of first subshell.

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Olegator [25]

Answer:

D. Gases were released to the atmosphere

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3 years ago

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3 years ago

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Rama09 [41]

Answer:

Explanation:

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3 years ago

Read 2 more answers

To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?

poizon [28]

We know that to relate solutions of with the factors of molarity and volume, we can use the equation: $M_{1} V_{1} = M_{2} V_{2}$

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M $H_{2} SO_{4}$ is the left side of the equation. Then we have:

$(18 M)(0.050 L)=(4.35M) V_{2}$

We can then solve for $V_{2}$ :

$V_{2}= \frac{(18M)(0.05L)}{4.35M}$ and $V_{2} =0.21 L$ or $210 mL$

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.

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4 years ago