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wlad13 [49]
3 years ago
10

A road that rises 1 ft for every 100 ft traveled

Physics
1 answer:
Lana71 [14]3 years ago
6 0

Explanation:

6% grade

=> Rises 6 feet for every 100 feet traveled

This would mean that tanx = 6/100.

=> x = tan^-1(6/100) = 3.4°. (1d.p.)

Hence the road is inclined at an angle of 3.4° above the horizontal.

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the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ
stiks02 [169]

Answer:

D. Increases from pole to equator

Explanation:

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3 years ago
What distance is covered by an airplane traveling at a velocity of 660 miles per hour in 3.5 hours?
N76 [4]

As per the question, the velocity of the airplane [v] = 660 miles per hour.

The total time taken by airplane [t] = 3.5 hours.

We are asked to determine the total distance travelled by the airplane during that period.

The distance covered [ S] by a body is the product of velocity with the time.

Mathematically distance covered = velocity × total time

                                                      S = v × t

                                                        = 660 miles/hour ×3.5 hours

                                                        = 2310 miles.

Hence, the total distance travelled by the airplane in 3.5 hour is 2310 miles.

4 0
3 years ago
The weight of an object on a planet depends on not only its mass but also on its distance from the planest center. this table li
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Uranus is much much larger than Earth, so the distance from the planet's center is much much greater
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3 years ago
Consider the rocket in the image. Which unbalanced force accounts for the direction of the net force of the rocket ?
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Answer:

unbalenced force

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3 0
3 years ago
Read 2 more answers
A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the
bazaltina [42]

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = 2\times 10^{-3}

Extended by = 0.25mm = 0.25\times 10^{-3}

Based on the above information, the calculation is as follows

a. The Stress of the wire is

= \frac{force\ applied}{area\ of \ circle}

here area of circle = perpendicular to the are i.e cross-sectional  i.e

= \frac{\pi d^{2}}{4}

= \frac{\pi(2\times 10^{-3})^2}{4}

Now place these above values to the above formula

= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}

= 5 \times 10^{-5}

3 0
3 years ago
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