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LiRa [457]
2 years ago
12

Hellowhat is zenith define it ?​

Physics
1 answer:
sertanlavr [38]2 years ago
4 0

Answer:

hi,

When one stands at a particular place, the point in the sky directly above the head is called Zenith.

Explanation:

hope it helps(≡^∇^≡)

good day

thank u ✅

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An airplane starts from rest and accelerates at a constant rate of 3.00 m/s2 for 30.0 s before leaving the ground. a. How far di
rosijanka [135]

The formula we can use in this case is:

d = v0t + 0.5 at^2

v = at + v0

where,

d = distance travelled

v0 = initial velocity = 0 since at rest

t = time travelled

a = acceleration

v = final velocity when it took off

 

a. d = 0 + 0.5 * 3 * 30^2

d = 1350 m

 

b. v = 3 * 30 + 0

<span>v = 90 m/s</span>

8 0
3 years ago
Ice core samples are used to measure…
blsea [12.9K]

Answer:

the correct answer is A

6 0
2 years ago
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The combustion of propane (C3H8) in the presence of excess oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) W
zimovet [89]

Answer:

1.2

Explanation:

2.0 mol O₂ × (3 mol CO₂ / 5 mol O₂) = 1.2 mol CO₂

4 0
3 years ago
A)If your torsion balance deflects to an angle of 10° when your two spheres are 40cm apart, what angle will it deflect to when t
svp [43]

Answer:

Explanation:

Given

for \theta=10^{\circ}

Sphere are d=40\ cm

when sphere d_2=10\ cm apart suppose deflection is \theta _2

We know

F=k_t\cdot \theta

Where F=force between charged particle

\theta =Deflection

F=\frac{kQ_1Q_2}{r^2}=k_t\cdot \theta

\theta =\frac{k}{k_t}\times \frac{Q_1Q_2}{r^2}----1

thus \theta \propto \frac{1}{r^2}

for \theta _2

\frac{\theta _1}{\theta _2}=(\frac{r_2}{r_1})^2

\theta _2=16\times \theta _1

\theta _2=160^{\circ}

(b)for 10^{\circ} deflection Potential v_1=8\ kV

Electric Potential is V=\frac{kQ}{r}

Q=\frac{V\cdot r}{k}

where V=voltage

k=constant

r=distance between charges

Put value of Q in equation 1

\theta =\frac{k}{k_t}\times \frac{V^2r^2}{k^2}

\theta =\frac{V^2r^2}{k\cdot k_t}

thus \theta \propto V^2

therefore

\frac{\theta _1}{\theta _2}=(\frac{V_1}{V_2})^2

\frac{10}{\theta _2}=(\frac{8}{4})^2

\theta _2=\frac{10}{4}=2.5^{\circ}

5 0
3 years ago
20 regras diferentes do basquete
gulaghasi [49]

Regra dos 5 segundos: o jogador pode ficar em contato com a bola no máximo 5 segundos. Regra dos 3 segundos: um jogador não pode permanecer mais do que 3 segundos dentro da área do garrafão sem a bola. Regra dos 8 segundos: a equipe tem até 8 segundos para passar da zona de defesa para a zona de ataque.

Eu só tenho estes, espero que eles o ajudem!

8 0
3 years ago
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