If the solutions of p(x) = 0 are -14 and 11, which function could be p?

Mathematics

1 answer:

dem82 [27]2 years ago

3 0

Answer:

p^2+3p-154=0

Step-by-step explanation:

(p+14)*(p-11)=0

p+14=0

p=-14

p-11=0

p=11

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your teacher is giving you a test worth 100 points that contains 40 questions. there are 2point questions on the test. how many

kykrilka [37]

100 = 2t + 4f
40= t + f
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get t or f by itself first.

f = 40 - t : Then substitute it back into for f in the other equation
100 = 2t + 4f
100= 2t +4(40-t)
100= 2t + 160 - 4t
100 = -2t + 160
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-60 = -2t
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3 years ago

(-2^3x2^-1)^-2=1/16 Showing exponent properties how can this be done?

rjkz [21]

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101/25 converted to a mixed number

mamaluj [8]

Hi
Let me help you out

101/25 is a in proper fraction.
To change the in proper fraction to a proper fraction you have to see which number is close to 101 by multiplying numbers to 25. You can also divide 101 by 25 which is 4 remainder 1.
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2 years ago

HELP ASAP!! Identify the matrix transformation of ΔPQR, which has coordinates P(−5, −2),Q(−6, −3), and R(−2, −3), for reflection

podryga [215]

Answer:

Matrix transformation = $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ .

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-5\\-2\end{array}\right]$ = (5,-2)