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Varvara68 [4.7K]
3 years ago
8

If the solutions of p(x) = 0 are -14 and 11, which function could be p?

Mathematics
1 answer:
dem82 [27]3 years ago
3 0

Answer:

p^2+3p-154=0

Step-by-step explanation:

(p+14)*(p-11)=0

p+14=0

p=-14

p-11=0

p=11

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Write the percent as a decimal 0.12%
11Alexandr11 [23.1K]
"Percent" means literally per one-hundred so

0.12/100

0.0012
7 0
3 years ago
I. A rhombus is a special type of square. II. A rectangle is a special type of rhombus. III. A trapezoid is a special type of pa
Kobotan [32]

Answer: I. only

--------------------------------------------------------------------------------------------------------------

Explanation :

II. False. a rectangle is a special type of rhombus since a rhombus has all sides equal, while a rectangle has all angles equal. A rhombus has opposite angles equal, while a rectangle has opposite sides equal.  The diagonals of a rhombus intersect at equal angles, while the diagonals of a rectangle are equal in length.

I.  True. A square is a special case of a rhombus, because it has four equal-length sides and goes above and beyond that to also have four right angles. Every square you see will be a rhombus, but not every rhombus you meet will be a square.

III. False.  Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. A trapezoid can never be a parallelogram. The correct answer is that all trapezoids are quadrilaterals.

4 0
3 years ago
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
What might your scatter plot depict
dimulka [17.4K]

Answer:

It is supposed to predict the points, or the correlational relationship between variables.

Step-by-step explanation:

8 0
3 years ago
A total of 276 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t
NISA [10]
Consider the number of the adult tickets is x
X+2x=276
3x=276
X=92
So the student tickets is =184
4 0
3 years ago
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