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Alisiya [41]
3 years ago
11

Briefly describe the difference between the behaviorist, nativist, and interactionist language acquisition theories.

Physics
1 answer:
Over [174]3 years ago
4 0

Answer:

Described below

Explanation:

- The behaviorist theories: This theory is of the claim that language is learned through the means of reinforcement and imitation. This means that little children can mimic the language of individuals around them and also receive reinforcement to correct the formation of their words. Thereafter, words not reinforced will eventually no longer be in use.

- The nativist theories: This theory is of the claim that individuals possess an innate process which is used in language learning and is widely known as "language acquisition device" (LAD). This device is used to assist in helping them automatically learn languages.

-The interactionist theories: This theory is of the claim that innate processes which is also referred to as genetic predispositions and learning experiences from the environment both help in language development.

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Starting from rest, a 2.1x10^-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exert
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Answer:

a) The flea's speed when it leaves the ground is v=1.88m/s

b) The flea move 18cm upward while it is pushing off

Explanation:

Hi

<u>Knwons</u>

Mass m=2.1\times 10^{-4} kg, Work W=3.7\times 10^{-4} J and Force F=0.41N

a) Here we are going to use W=\frac{1}{2} mv^{2}, so v=\sqrt{\frac{2W}{m} }= \sqrt{\frac{2(3.7\times 10^{-4} J)}{2.1\times 10^{-4} kg} }=1.88m/s

a) Here we are going to use W=mgh, so h=\frac{W}{mg}= \frac{3.7\times 10^{-4} J}{(2.1\times 10^{-4} kg)(9.8m/s^{2})} =0,1797m or 18cm approx.

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A 3 kg toy car with a speed of 7 m/s collides head-on with a 2 kg car traveling in the opposite direction with a speed of 5 m/s.
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Answers:

kinetic energy lost = 86.4J

Explanation:

let Kf be the kinetic energy after the collision and Ki be the kinetic energy before the collision. let the 3kg car be 1 and 2kg car be 2.

Kf = K1(f) + K2(f)

Ki = K1(i) + k2(i)

loss in kinetic energy = Kf - Ki

                                 = 1/2(3)(2.20)^2 + 1/2(2)(2.20)^2 - 1/2(3)(7)^2 - 1/2(2)(-5)^2

                                 = 12.1 - 98.5

                                 = -86.4 J

therefore, the kinetic energy lost in the collision is 86.4 J.

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