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AlexFokin [52]
3 years ago
14

A tiger runs at 58 km/h [S]. What is the displacement of the tiger in 38 s?

Physics
1 answer:
Artyom0805 [142]3 years ago
3 0
58 K/h = 58000/3600= 16.1 m/s
In 38 s displacement is 38x16.1= 612.2 m
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The unit used to measure electric current is the ampere (A). Now, assume that the current delivered at a wall socket reaches the
pav-90 [236]

Answer:

T = 0.017s

Explanation:

period is the time it takes a particle to make one oscillation

An electric current is periodic in nature

The current reaches 3.8A  ten times.  

So there must have been 10 cycles (10 periods) in 0.17s.   let 'T'  be the period:

T=\frac{t}{n}

t is the total time interval

n is the number of oscillations

T=\frac{0.17}{10}

10T = 0.17

T = 0.17/10 = 0.017s

8 0
3 years ago
A wave has a frequency of 6 Hz and a speed of 30 m/s. What is the wavelength of the wave?
Helen [10]

Answer:

D. 5m

Explanation:

fλ = c, where f is frequency, λ is wavelength and c is speed.

6λ=30

λ=30/6=5

5 0
3 years ago
What real-world examples show no work begin done? Can you think of examples other than resisting the force of gravity?
irga5000 [103]
Oh my gosh !  Resisting the force of gravity always DOES involve doing work.
If no work is being done, then you're NOT resisting the force of gravity.

Example:

-- ball rolling on the floor . . . no work
-- ball rolling up a ramp . . . work being done
-- ball rolling down a ramp . . . work being done, BY gravity

6 0
4 years ago
Read 2 more answers
What is the meaning of the word solar in the article "Fire Up the Sun"?
SpyIntel [72]

Answer:

B) Caused by the Sun

Explanation:

If you look at a picture of a solar system, you will see the sun in the middle. The sun is the powerhouse of the solar system. So that means that the sun is the biggest star and can provide enough light to reach earth and keep it lit.

4 0
3 years ago
A 108 kg clock initially at rest on a horizontal floor requires a 653 N horizontal force to set it in motion. After the clock is
kifflom [539]

Answer:

\mu_s=0.61

\mu_k=0.49

Explanation:

Given that,

Mass of the clock, m = 108 kg

When the clock is not moving, force acting on it, F_1=653\ N

For the clock in motion, force acting on it, F_2=527\ N

To find,

\mu_s\ and\ \mu_k

Solution,

When an object is at rest, the force acting on it is called force due to static friction and if the object is in motion, the force acting on its called force due to kinetic friction.

Let \mu_s is the coefficient of static friction. Force is given by :

F_s=\mu_smg

\mu_s=\dfrac{F_s}{mg}

\mu_s=\dfrac{653}{108\times 9.8}

\mu_s=0.61

Let  \mu_k is the coefficient of kinetic friction. Force is given by :

F_k=\mu_kmg

\mu_k=\dfrac{F_k}{mg}

\mu_k=\dfrac{527}{108\times 9.8}

\mu_k=0.49

8 0
3 years ago
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