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iren2701 [21]
2 years ago
5

Illustrate the crowbar protection for silicon controlled rectifier​

Engineering
1 answer:
julsineya [31]2 years ago
4 0

Answer:

The SCR over voltage crowbar or protection circuit is connected between the output of the power supply and ground. ... It also clamps the gate voltage at ground potential until the Zener turns on. The capacitor C1 is present to ensure that short spikes to not trigger the circuit.

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**Please Help ASAP**
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Explanation:

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Consider a mixing tank with a volume of 4 m3. Glycerinflows into a mixing tank through pipe A with an average velocity of 6 m/s,
Svetach [21]

This question is incomplete, the complete question as well as the missing diagram is uploaded below;

Consider a mixing tank with a volume of 4 m³. Glycerin flows into a mixing tank through pipe A with an average velocity of 6 m/s, and oil flow into the tank through pipe B at 3 m/s. Determine the average density of the mixture that flows out through the pipe at C. Assume uniform mixing of the fluids occurs within the 4 m³ tank.

Take p_o = 880 kg/m³ and p_{glycerol = 1260 kg/m³    

 

Answer:

the average density of the mixture that flows out through the pipe at C is 1167.8 kg/m³  

Explanation:

Given that;

Inlet velocity of Glycerin, V_A = 6 m/s

Inlet velocity of oil, V_B = 3 m/s  

Density velocity of glycerin, p_{glycerol = 1260 kg/m³

Density velocity of glycerin, Take p_o = 880 kg/m³

Volume of tank V = 4 m

from the diagram;

Diameter of glycerin pipe, d_A = 100 mm = 0.1 m

Diameter of oil pipe, d_B = 80 mm = 0.08 m

Diameter of outlet pipe d_C = 120 mm = 0.12 m

Now, Appling the discharge flow equation;

Q_A + Q_B = Q_C

A_Av_A + A_Bv_B = A_Cv_C

π/4 × (d_A)²v_A + π/4 × (d_B )²v_B = π/4 × (d_C)²v_C

we substitute

π/4 × (0.1 )² × 6 + π/4 × (0.08 )² × 3 = π/4 × (0.12)²v_C

0.04712 + 0.0150796 = 0.0113097v_C

0.0621996 = 0.0113097v_C

v_C = 0.0621996 / 0.0113097

v_C  = 5.5 m/s

Now we apply the mass flow rate condition

m_A + m_B = m_C

p_{glycerin}A_Av_A + p_0A_Bv_B = pA_Cv_C  

so we substitute

1260 × π/4 × (0.1 )² × 6 + 880 × π/4 × (0.08 )² × 3 = p × π/4 × (0.12)² × 5.5

1260 × 0.04712 + 880 × 0.0150796 = p × 0.06220335

59.3712 + 13.27 = 0.06220335p  

72.6412 = 0.06220335p    

p = 72.6412 / 0.06220335

p =  1167.8 kg/m³  

Therefore, the average density of the mixture that flows out through the pipe at C is 1167.8 kg/m³  

4 0
3 years ago
The velocity field of a flow is given by where x and y are in feet. Determine the fluid speed at points along the x axis; along
lora16 [44]

Answer:

Using the formula

V =20y/(x^2+y^2)^1/2 - 20x/(x^2+y^2)^1/2

Hence fluid speed at x axis =20x/(x^2+y^2)^1/2

While the fluid speed at y axis =20y/(x^2+y^2)^1/2

Now the angle at 1, 5

We substitute into the formula above

V= 20×5/(1+25)^1/2= 19.61

For x we have

V = 20× 1/(1+25)^1/2= 3.92

Angle = 19.61/3.92= 5.0degrees

Angel at 5, and 2

We substitute still

V = 20×5/(2+25)^1/2=19.24

At 2 we get

V= 20×2/(2+25)^1/2=7.69

Dividing we get 19.24/7.69=2.5degrees

At 1 and 0

V = 20/(1)^1/2=20

At 0, v =0

Angel at 2 and 0 = 20degrees

At 5 and 2

V = 100/(25+ 4)^1/2=18.56

At x = 2

40/(√29)=7.43

Angle =18.56/7.43 = 2.49degrees.

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