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3 years ago

Illustrate the crowbar protection for silicon controlled rectifier

Engineering

1 answer:

julsineya [31]3 years ago

4 0

Answer:

The SCR over voltage crowbar or protection circuit is connected between the output of the power supply and ground. ... It also clamps the gate voltage at ground potential until the Zener turns on. The capacitor C1 is present to ensure that short spikes to not trigger the circuit.

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If the 1550-lb boom AB, the 190-lb cage BCD, and the 169-lb man have centers of gravity located at points G1, G2 and G3, respect

Natasha2012 [34]

Answer:

hello the required diagram is missing attached to the answer is the required diagram

7.9954 kip.ft

Explanation:

AB = 1550-Ib ( weight acting on AB )

BCD = 190 - Ib ( weight of cage )

169-Ib = weight of man inside cage

Attached is the free hand diagram of the question

calculate distance $x!$

= cos 75⁰ = $\frac{x^!}{10ft}$

$x! = 10 * cos 75^{o}$ = 2.59 ft

calculate distance x

= cos 75⁰ = $\frac{x}{30ft}$

x = 30 * cos 75⁰ = 7.765 ft

The resultant moment produced by all the weights about point A

∑ Ma = 0

Ma = 1550 * $x!$ + 190 ( x + 2.5 ) + 169 ( x + 2.5 + 1.75 )

Ma = 1550 * 2.59 + 190 ( 7.765 + 2.5 ) + 169 ( 7.765 + 2.5 + 1.75 )

= 4014.5 + 1950.35 + 2030.535

= 7995.385 ft. Ib ≈ 7.9954 kip.ft

6 0

4 years ago

A mass of 12 kg saturated refrigerant-134a vapor is contained in a piston-cylinder device at 240 kPa. Now 300 kJ of heat is tran

Ket [755]

Answer:

I = 12.706 Amps

Explanation:

Given:

- The mass of saturated R-134a m = 12 kg

- The initial Conditions

P_1 = 240 KPa

Saturated Vapor

- The final Conditions

P_2 = 240 KPa

T_2 = 70° C

- The amount of Heat transferred Q_in = 300 KJ

- The voltage of current source V = 110 V

- The current supplied by the source = I

- The time duration Δt = 6 min

Find:

Determine the current supplied I.

Solution:

- Look-up enthalpies h_1 and h_2 at both states using Tables A-11 and A-13.

P_1 = 240 KPa

Saturated Vapor ----------> h_1 = h_g = 247.32 KJ/kg

P_2 = 240 KPa

T_2 = 70° C ----------> h_2 = 314.53 KJ/kg

- Using First Thermodynamic Law, set up an energy balance:

E_in - E_out = ΔE_system

Q_in + W_electric,in - W_out = Δ U

Q_in + V*I*Δt - W_out = Δ U

Q_in + V*I*Δt = Δ H

Q_in + V*I*Δt = m*( h_2 - h_1 )

- Make the current I the subject of the expression above:

V*I*Δt = m*( h_2 - h_1 ) - Q_in

I = [ m*( h_2 - h_1 ) - Q_in ] / V*Δt

- Plug in the values in the expression derived above and evaluate current of source I:

I = [ 12*( 314.53 - 247.32 ) - 300 ]*1000 / 110*6*60

I = 12.706 Amps

- The required source of current is I = 12.706 Amps.

4 0

3 years ago

Whats the best used for Arch bridge

SOVA2 [1]

Answer:

China has also been constructing arch bridges for many years. They built the Zhaozhou Bridge in 605 AD, and it is still around today! Modern arch bridges use materials such as concrete, steel and iron.

Explanation:

6 0

3 years ago

what is the expected life 1 inch diameter bar machined from AISI 1020 CD Steel is subjected to alternating bending stress betwee

Alexeev081 [22]

Answer:

1.287 *10⁷ cycles.

Explanation:

See attached pictures.

3 0

3 years ago

A 1,040 N force is recorded on a hemispherical vane as it redirects a 2.5 cm- blade diameter water jet through a 180 angle. Dete

Alex777 [14]

This question is incomplete, the complete question is;

A 1,040 N force is recorded on a hemispherical vane as it redirects a 2.5 cm- blade diameter water jet through a 180 angle.

Determine the velocity of the flowing water jet if the blade is assumed to be frictionless.

Answer: the velocity of the flowing water jet is 32.55 m/s assuming the blade is frictionless

Explanation:

Given that;

Force Ft = 1040 N

diameter d = 2.5 cm = 0.025 m

we know that; force acting on Hemispherical plate is;

Ft = 2δav²

where

a is area = π/4(0.025)²

δ is density of water = 1000 kg/m³

v is velocity = ?

now we substitute

1040 = 2 × 1000 × (π/4(0.025)²) × v²

1040 = 0.9817v²

v² = 1040 / 0.9817

v² = 1059.3867

v = √1059.3867

v = 32.5482 ≈ 32.55 m/s

Therefore the velocity of the flowing water jet is 32.55 m/s assuming the blade is frictionless

8 0

3 years ago

Illustrate the crowbar protection for silicon controlled rectifier​

Illustrate the crowbar protection for silicon controlled rectifier