Question

Forces of 11.9 N north, 19.1 N east, and 14.4 N south are simultaneously applied to a 3.77 kg mass as it rests on a frictionless air table. What is the magnitude of its acceleration?

Answer 1

Force Vector = <19.1i+11.9j-14.4j>N
Force Vector = <19.1i-2.5j>N
Acceleration Vector =(Force Vector)/mass
Acceleration Vector =<19.1i-2.5j>N/3.77
Acceleration Vector =<5.0663i-0.6631j>m/s^2
|a| = (5.0663^2+(-0.6631)^2)^0.5
|a| = 5.11 (m/s^2)