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Alenkinab [10]
3 years ago
5

2 − 36 = 0 Solve by square roots

Mathematics
1 answer:
Paraphin [41]3 years ago
7 0

Answer:

no solution

Step-by-step explanation:

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30 points for whoever helps George Washington...please
faust18 [17]

Answer:

A

Step-by-step explanation:

A is equal to 5d-5

I just went through all eh choices

It can’t be b or c becuase when distributed, it automatically is -5d+25 or vice versa with a different sign so their out

D is impossible becuase you can’t jsut flip a subtraction problem

And A is possible because adding a negative basically means subtracting so if flipped The signs have to change

8 0
2 years ago
What is the slope of the line that passes through the points (8, -4)(8,−4) and (6, 2) ?(6,2)?
Art [367]
The slope is 2-2/6-6 which is zero . So the slope is no slope
6 0
2 years ago
What is 2 1/3 x 3 4/9
bogdanovich [222]

Answer:

is equal to 8 1/27

Step-by-step explanation:

(2

1

3

)(3

4

9

)

=

7

3

(3

4

9

)

=

7

3

(

31

9

)

=

217

27

=8

1

27

7 0
3 years ago
Read 2 more answers
A rectangular box is 5 in. ​wide, 5 in. ​tall, and 4 in. long. What is the diameter of the smallest circular opening through whi
Katyanochek1 [597]

Answer:

7 (7.07106781187)

Step-by-step explanation:

All you have to do is find the diameter of the rectangle from two farthest corners. To do this, use the Pythagorean Theorem

(5^2) + (5^2) = c^2

25 + 25 = c^2

50 = c^2

7 ≈ c

8 0
3 years ago
In a volleyball game, a player on one team spikes the ball over the net when the ball is 10 feet above the court. The spike driv
Fynjy0 [20]

Answer:

4.75 seconds

Step-by-step explanation:

Initial height of the ball from the ground = 10 feet

Upward initial velocity given = 55 feet per second

Value of g ( acceleration due to gravity) = 32.2 feet per s²

Motion of the ball:

The ball first goes vertically upwards, gravity decelerates the body and it momentarily comes to rest at a point in its upward trajectory, which is the point of maximum height. From this point, to the ground, the ball behaves as a freely dropped body.

Till the ball reaches its maximum height:

u = + 55

v = 0 ( final velocity is zero)

a = - 32.2 (since it is deceleration)

we know that <em>v = u + at </em>

⇒    0 = 55 - 32.2t

⇒  t = 1.7 s

Also , we have <em>s = ut + (1/2)at²</em>

Here, s is the maximum height from the point where ball is thrown

So,     s = 55(1.7) - (0.5)(32.2)(1.7)(1.7)

⇒ s = 140 feet

So at a height of 140 feet + 10 feet (initial height) = 150 feet, the ball acts as a freely dropped body.

Here,      u = 0

               a = +32.2

               s= 150

<em>s = ut + (1/2)at²</em>

⇒  150 = 0.5 ( 32.2) (t²)

⇒  t² = 300/32.2 = 9.31

⇒ t = 3.05 sec

So total time = 1.7 + 3.05 = 4.75 seconds

8 0
3 years ago
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