Answer:
![2HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)](https://tex.z-dn.net/?f=2HF%28aq%29%2BBa%28OH%29_2%28aq%29%5Crightarrow%20BaF_2%28s%29%2BH_2O%28l%29)
Explanation:
Hello!
In this case, since the neutralization reaction between hydrofluoric acid and barium hydroxide (both aqueous) produce insoluble barium fluoride and liquid water, we can write the chemical reaction as follows:
![HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)](https://tex.z-dn.net/?f=HF%28aq%29%2BBa%28OH%29_2%28aq%29%5Crightarrow%20BaF_2%28s%29%2BH_2O%28l%29)
However, it needs to be balanced as hydrogen and fluorine are not properly balanced, therefore, we obtain:
![2HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)](https://tex.z-dn.net/?f=2HF%28aq%29%2BBa%28OH%29_2%28aq%29%5Crightarrow%20BaF_2%28s%29%2BH_2O%28l%29)
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Substituting the values into the equation:
2.7 x 10⁻⁵ = k(0.1)²
k = 2.7 x 10⁻³ M⁻¹s⁻¹
3.00 M means 3.00 mol/L. So if you want 500 mL=0.5 L, it needs 3.00 mol/L * 0.5 L = 1.50 mol. For NaCl, the molar mass is 23+35.5=58.5 g/mol. So the amount of NaCl needed is 1.50*58.5=87.75 g. So the answer is 87.75 grams.
Explanation:
option B is the correct answer
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