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Kobotan [32]
3 years ago
13

During oxidation of ethanol to ethanol, the ethanol formed was found to be contaminated with unconverted ethanol, describe how y

ou would obtain ethanal free from ethanol​
Chemistry
2 answers:
Dafna1 [17]3 years ago
4 0

<u><em>The process of how we would obtain </em></u><u><em>ethanal</em></u><u><em> </em></u><u><em>free</em></u><u><em> from ethanol is described in the explanations below. </em></u>

<u><em /></u>

  • In Chemistry, Ethanol undergoes oxidation in the presence of sodium dichromate plus sulphuric acid to yield ethanal and water.

The procedure for achieving this in the laboratory is as follows;

  • Step 1; Measure a quantity of a solution of sodium dichromate acidified in a dilute sulphuric acid and pour into a test tube.

  • Step 2; Add excess <em>ethanol</em>. This is because if we don't do so there will be plenty of oxidizing agent to carry out a second operation which changes the aldehyde to ethanoic acid. However, we need only the aldehyde.

  • Step 3; When the aldehyde ethanal begins to form which will be evident by the change in the colour of solution from <em>orange to green</em>, then the mixture should be distilled from the test tube and tbethe aldehyde collevted so that it doesn't undergo additional oxidation into ethanoic acid.

Read more at; https://brainly.in/question/18574624

Novosadov [1.4K]3 years ago
4 0

Answer:

Ethanol is oxidised by acidified sodium dichromate in a test tube reaction, firstly to form ethanal (acetaldehyde), and with further oxidation, ethanoic acid (acetic acid)

Procedure

Place about 3 cm3 of acidified sodium dichromate solution in a boiling tube.

Use a teat pipette to add 5–7 drops of ethanol, with shaking.

Cool the mixture in the tube under a tap. Note the sweetish smell of ethanal (acetaldehyde) at first, then becoming sharper as oxidation continues and forms ethanoic acid (acetic acid).

When the reaction has subsided, the mixture can be warmed gently; the smell of ethanoic acid will become more noticeable.

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Be sure to answer all parts.
djyliett [7]

The number of moles contained in each of the question are a) 3.935 and b) 0.001165 mol.

<h3>What are moles?</h3>

Moles are a quantity or amount of a substance. Denoted by n.

To calculate moles, mass is divided by the molar mass

n = m/M

mass is divided by the molar mass

a) 230 grams of NaCl

n = m/M

molar mass of NaCl is 58.44 g/mol

n = 230 / 58.44 = 3.935 mol

b) 0.210 g of aspirin

n = m/M

molar mass of aspirin is 180.158 g/mol

n = 0.210 / 180.158 = 0.001165 mol

Thus, the moles are a) 3.935 and b) 0.001165 mol.

Learn more about moles

brainly.com/question/26416088

#SPJ1

4 0
2 years ago
A sample of gas has a mass of 827 mg . Its volume is 0.270 L at a temperature of 88 ∘ C and a pressure of 975 mmHg . Find its mo
avanturin [10]

Steps:

Mw = w * R * T / p * V

T = 88 + 273 => 361 K

p = 975 mmHg in atm :

1 atm  = 760 mmHg

975 mmg / 760 mmHg =>  1.28 atm

Therefore:

= 0.827 * 0.0821 * 361 /  1.28 * 0.270

=  24.51 / 0.3456

molar mass =  70.92 g/mol



7 0
3 years ago
Which of the following is not an example of an externality?
irina [24]

Answer:

option A

Explanation:

because acid comes from preparation of fossil fuel

7 0
3 years ago
Which rule is used when writing the name of an ionic bass
jonny [76]
The chemical name begins with Hydro The Chemical name ends with hydroxide and the ide ending is changed to ic also the polyatomic ate ending changed to ic
8 0
3 years ago
Read 2 more answers
Calculate the vapor pressure of water above a solution prepared by dissolving 28.5 g of glycerin (c3h8o3) in 135 g of water at 3
pshichka [43]
Data:

<span>Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.

Quesiton: Vapor pressure of water

Solution:

Raoult's Law: </span><span><span>The vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature  multiplied by its mole fraction.

Formula: p = Xsolvent * P pure solvent

X solvent = moles solvent / moles of solution

molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol

moles of solvent = 135 g of water / 18.0 g/mol = 7.50 mol

molar mass of C3H8O3 = 3*12.0 g/mol + 8*1 g/mol + 3*16g/mol = 92 g/mol

moles of solute = 28.5 g / 92.0 g/mol = 0.310 mol

moles of solution = moles of solute + moles of solvent = 7.50mol + 0.310mol = 7.810 mol

Xsolvent = 7.50mol / 7.81mol = 0.960

p = 233.7 torr * 0.960 = 224.4 torr

Answer: 224.4 torr
</span> </span>
8 0
3 years ago
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