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3 years ago

A car generates 2552 N and weighs 2250 kg what is its rate of acceleration?

Physics

1 answer:

alisha [4.7K]3 years ago

3 0

Answer:

a = 2552/2250= 1.00 m/s^2

.................

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Object A is positively charged. Object A and Object B

Hoochie [10]

B (+), C (-), D (-), E (+), F (-)

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2 years ago

(1 point) Find a linearly independent set of vectors that spans the same subspace of R3R3 as that spanned by the vectors ⎡⎣⎢3−1−

Natalka [10]

Answer:

Explanation:

$A=\left[\begin{array}{ccc}3&-9&-3\\-1&2&0\\-2&3&-1\end{array}\right] \\\\R_2\rightarrow 3R_2+R_1,R_3\rightarrow 3R_3+2R_1\\\\=\left[\begin{array}{ccc}3&-9&-3\\0&-3&-3\\0&-9&-9\end{array}\right] \\\\R_3\rightarrow 3R_3-9R_2\\\\=\left[\begin{array}{ccc}3&-9&-3\\0&-3&-3\\0&0&0\end{array}\right]$

This is the row echelon form of A. This means that only two of the vectors in our set are linearly independent. In other words, the first two vectors alone will span the same subspace of $R^4$ as all three vectors.

Therefore, the linearly independent spanning set for the subspace is

$\left[\begin{array}{ccc}3\\-1\\-2\end{array}\right] \left[\begin{array}{ccc}-9\\2\\3\end{array}\right] \left[\begin{array}{ccc}3\\0\\-1\end{array}\right]$

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3 years ago

The average turtle can walk 3 meters per hour, how far can the turtle walk in three minutes

Likurg_2 [28]

Answer:

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3 years ago

A stone with a mass of 0.70 kg is attached to one end of a string 0.70 m long. The string will break if its tension exceeds 65.0

mixas84 [53]

Answer:v=8.06 m/s

Explanation:

Given

mass of stone $m=0.7 kg$

length of string $L=0.7 m$

Maximum Tension $T=65 N$

the string will not break if Centripetal Force is less than maximum tension

$T=\frac{mv^2}{r}$

$65=\frac{0.7\times v^2}{0.7}$

$v^2=65$

$v=\sqrt{65}$

$v=8.06 m/s$

4 0

3 years ago

If a moving body of mass 100g has kinetic energy 45 joules, what will be it's velocity?

Pavel [41]

Answer:

$\boxed{\pink{\sf Velocity \ of \ the \ body \ is \ 30m/s .}}$

Explanation:

Given that a body is moving which has a mass of 100g. And its Kinetic energy is 45 Joules . We need to find its velocity . So ,

$\boxed{\red{\bf Kinetic\: Energy =\dfrac{1}{2}mv^2 }}$

Now here mass is in grams. So converting it into SI units we have , 100/1000 kg = 0.1 kg

$\implies KE =\dfrac{1}{2}mv^2 \\\\\implies 45 J = \dfrac{1}{2}\times \dfrac{1}{10} kg \times v^2 \\\\\implies v^2 = 45 \times 20 \\\\\implies v^2 = 900 m^2/s^2 \\\\\implies v =\sqrt{900 m^2/s^2} \\\\\underline{\boxed{\blue{\tt \implies Velocity = 30m/s }}}$

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3 years ago