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Stells [14]
3 years ago
14

Are inic bonds formed when electrons are equally or unequally shared

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
8 0

The electrons are unequally shared. The electronegative element receives the electrons from the electropositive one.

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What is the relationship between mole, Avogadro number and mass?
weeeeeb [17]

Answer:

The mass of one mole of a substance is equal to that substance's molecular weight. ... water is 18.015 atomic mass units (amu), so one mole of water weight 18.015 grams. ... Avogadro's number is a proportion that relates molar mass on an atomic ... one molecule of water (H2O), one mole of oxygen (6.022×1023 of O atoms)

5 0
3 years ago
Why the mixture of bromine and ethane is discoloured when left in the sun​
DENIUS [597]

Answer:

In the presence of UV light, ethane will react with bromine in a substitution reaction. UV light is the condition under which the reaction will occur so it is written above the arrow in the chemical equation. As the reaction proceeds, the intensity of the re-brown colour of the bromine water decreases.

8 0
3 years ago
Read 2 more answers
The half-life of tritium is 12.3 years. If 48.0 mg of tritium is released from a nuclear power plant during the course of a mish
Thepotemich [5.8K]

Half life is defined as the time when the final concentration reduced to half of the initial value.

Thus, for first half life, the remaining percentage of the reactant is 50 percent that is \frac{50}{100}=\frac{1}{2}

Now, for second half life, the remaining  percentage will be 50 percent of the remaining 50 percentage that is \frac{50}{2}=25 \frac{25}{100}=\frac{1}{4} or \frac{1}{2^{2}}

Thus, general formula for n  half lives =\frac{1}{2^{n}}

Now, 98.4 years is equal to eighth times 12.3 years that is \frac{1}{2^{8}} =\frac{1}{256} remaining material.

Therefore, mass of the nuclide will remain after 98.4 years= \frac{48.0 mg}{256}

= 0.1875 mg

Mass of remaining nuclide after 98.4 years =  0.1875 mg


4 0
4 years ago
Which statement is true for gases, but not for solids or liquids? A. The particles are in motion. B. The particles rarely touch
andriy [413]

Answer:

B. The particles rarely touch each other.

Explanation:

The particles of gases are far apart, so they rarely touch each other. The particles of liquids can slide past each other, and the particles of solids are locked in place next to each other.

In all three states of matter, the particles

  • Have a definite volume
  • Are in constant motion
  • Have kinetic energy
7 0
3 years ago
Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.850 atm
alekssr [168]

Answer:

(I). The gases are present at the end of the experiment  are O₂ and NO₂

(II).  The pressure of O₂ is 0.158 atm.

The pressure of NO₂ is 0.681 atm

The Pressure of NO is zero.

Explanation:

Given that,

Volume of large bulb = 6.00 L

Pressure = 0.850 atm

Volume of small bulb = 1.50 L

Pressure = 2.50 atm

Temperature = 22°C = 295 K

We need to calculate the moles in NO

Using formula of moles

n=\dfrac{PV}{RT}

Put the value into the formula

n=\dfrac{0.850\times6.00}{0.0821\times295}

n=0.211\ moles

We need to calculate the moles in O

Using formula of moles

n=\dfrac{PV}{RT}

Put the value into the formula

n=\dfrac{2.50\times1.50}{0.0821\times295}

n=0.155\ moles

The balance equation for the reaction is

2NO+O_{2}\Rightarrow 2NO_{2}

So, The gases are present at the end of the experiment  are O₂ and NO₂

We need to calculate the remaining moles of O₂

Using formula for remaining moles

Moles of  O₂ remaining = 0.155-\dfrac{0.211}{2}

Moles\ of \ O_{2}\ remaining =0.049\ moles

Moles of NO₂ = 0.211 moles

Total volume V=V_{l}+V_{s}

Put the value into the formula

V=6.00+1.50

V=7.5\ V

(2). If the gas was consumed completely

We need to calculate the pressure of O₂

Using formula of pressure

P=\dfrac{moles\times R\times T}{V}

Put the value into the formula

P=\dfrac{0.049\times0.0821\times295}{7.5}

P=0.158\ atm

We need to calculate the pressure of NO₂

Using formula of pressure

P=\dfrac{moles\times R\times T}{V}

Put the value into the formula

P=\dfrac{0.211\times0.0821\times295}{7.5}

P=0.681\ atm

If the gas was consumed completely

Then, Pressure of NO is zero.

Hence, (I). The gases are present at the end of the experiment  are O₂ and NO₂

(II).  The pressure of O₂ is 0.158 atm.

The pressure of NO₂ is 0.681 atm

The Pressure of NO is zero.

8 0
3 years ago
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