All categories

3 years ago

Two factors that determine whether a reaction will occur spontaneously

Chemistry

1 answer:

pogonyaev3 years ago

3 0

Two factors that determine whether a reaction will occur spontaneously are entalpy and entropy.

You might be interested in

Tris is a molecule that can be used to prepare buffers for biochemical experiments. It exists in two forms: Tris (a base) and Tr

ale4655 [162]

Solution :

For the reaction :

$\text{TrisH}^+ + H_2O \rightarrow \text{Trish}^- + H_3O^+$

we have

$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$

$=\frac{x^2}{0.02 -x}$

$=8.32 \times 10^{-9}$

Clearing $x$ , we have $x = 1.29 \times 10^{-5} \text{ moles of acid}$

So to reach $\text{pH} = 7.8 (\text{pOH}= 14-7.8=6.2)$ , one must have the $\text{OH}^-$ concentration of the :

$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$

So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.

$\text {n NaOH}=1.29 \times 10^{-5}+6.31 \times 10^{-7}$

$= 1.35 \times 10^{-5} \text{ moles}$

Volume NaOH $= 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \text{ mL}}{1 \text{ mol}} = 0.0135 \text{ mL}$

Tris mass $H^+ = 0.02 \text{ mol} \times 157.6 \text{ g/mol}=3.152 \text{ g}$

Now to prepare the said solution we must mix:

$3.152 \text{ g Tris H} + 0.0135 \text{ mL NaOH} \ 1 M$ gauge to 1000 mL with water.

3 0

3 years ago

While estimating the Caloric content of the chemical constituents present in the food item, the carbohydrate amount is discounte

Mashcka [7]

Answer:

Fiber is "Not Digestible"

Explanation:

Carbohydrates that contain fiber cannot be completely digested. the indigestible components of fiber are measured in the calorimeter, but they are not accessible for energy in the human body.

5 0

3 years ago

the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel

shtirl [24]

Answer: The entropy change of the process is $2.0\times 10^2J/K$

Explanation:

To calculate the entropy change for different phase at same temperature, we use the equation:

$\Delta S=n\times \frac{\Delta H_{f}}{T}$

where,

$\Delta S$ = Entropy change

n = moles of acetone = 6.3 moles

$\Delta H_{f}$ = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol (Conversion factor: 1 kJ = 1000 J)

T = temperature of the system = $-94.7^oC=[273-94.7]=178.3K$

Putting values in above equation, we get:

$\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K$

Hence, the entropy change of the process is $2.0\times 10^2J/K$

4 0

3 years ago

A woman is trying to make sweet tea, but she just can’t seem to get it sweet enough. Which method could help her dissolve more s

Gwar [14]

The answer is C.....

4 0

3 years ago

Read 2 more answers

a can of diet soda will float in water while a can of regular sugar soda will sink. which of these best describes why this would

Yuri [45]

I think the correct answer from the choices listed above is option A. A can of diet soda will float in water while a can of regular sugar soda will sink. This is due to the reason that the regular soda is more dense than the diet soda. Hope this answers the question.

5 0

3 years ago