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Elena L [17]
3 years ago
9

Look at the diagram below.

Chemistry
2 answers:
Ronch [10]3 years ago
8 0

Answer:

<h3>Ray 3 is the reflected ray</h3>

=>reflection of light may occur whenever light travels from a medium of a given refractive index into a medium with a different refractive index. In the most general case, a certain fraction of the light is reflected from the interface, and the remainder is refracted.

Kazeer [188]3 years ago
5 0

Answer:

3rd statment

Explanation:

ray 1 and 2 are same vertical line

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Calculate the enthalpy of the formation of butane, C4H10, using the balanced chemical equation and the standard value below:
zavuch27 [327]

Answer:

+125.4 KJmol-1

Explanation:

∆H C4H10(g) = -2877.6kJ/mol

∆H C(s)=-393.5kJ/mol

∆H H2(g) = -285.8

∆H reaction= ∆Hproducts - ∆H reactants

∆H reaction= (-2877.6kJ/mol) - [4(-393.5kJ/mol) +5(-285.8)]

∆H reaction= +125.4 KJmol-1

6 0
3 years ago
Please help me to answer this question.<br>i have to submit tomorrow.​
ratelena [41]

Answer:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

4 0
3 years ago
Please help me :( thank you so much and if you can show work I would really appreciate it
Katyanochek1 [597]

Answer:

D

Explanation:

On the left hand side there are a total of 4 hydrogen and 2 oxygen but on the right hand side there Is only 2 hydrogen and 1 oxygen

6 0
3 years ago
What is the mass of 0.60 moles of Al
KIM [24]

16 g. The mass of 0.60 mol Al is 16 g.

Molar mass of Al = 26.98 g/mol

Mass of Al = 0.60 mol Al x (26.98 g Al/1 mol Al) = 16 g Al

6 0
3 years ago
Read 2 more answers
Help please !!!!!!!!
Elena L [17]

Answer:

Option B. 2096.1 K

Explanation:

Data obtained from the question include the following:

Enthalpy (H) = +1287 kJmol¯¹ = +1287000 Jmol¯¹

Entropy (S) = +614 JK¯¹mol¯¹

Temperature (T) =.?

Entropy is related to enthalphy and temperature by the following equation:

Change in entropy (ΔS) = change in enthalphy (ΔH) / Temperature (T)

ΔS = ΔH / T

With the above formula, we can obtain the temperature at which the reaction will be feasible as follow:

ΔS = ΔH / T

614 = 1287000/ T

Cross multiply

614 x T = 1287000

Divide both side by 614

T = 1287000/614

T = 2096.1 K

Therefore, the temperature at which the reaction will be feasible is 2096.1 K

5 0
3 years ago
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