Answer:
4
Explanation:
Relationship between wavenumber and Rydberg constant (R) is as follows:
![wave\ number=R\times Z^2\frac{1}{n_1^2} -\frac{1}{n_1^2}](https://tex.z-dn.net/?f=wave%5C%20number%3DR%5Ctimes%20Z%5E2%5Cfrac%7B1%7D%7Bn_1%5E2%7D%20-%5Cfrac%7B1%7D%7Bn_1%5E2%7D)
Here, Z is atomic number.
R=109677 cm^-1
Wavenumber is related with wavelength as follows:
wavenumber = 1/wavelength
wavelength = 253.4 nm
![wavenumber=\frac{1}{253.4\times 10^{-9}} \\=39463.3\ cm^{-1}](https://tex.z-dn.net/?f=wavenumber%3D%5Cfrac%7B1%7D%7B253.4%5Ctimes%2010%5E%7B-9%7D%7D%20%5C%5C%3D39463.3%5C%20cm%5E%7B-1%7D)
Z fro Be = 4
![39463.3=109677\times 4^2(\frac{1}{n_1^2} -\frac{1}{5^2})\\39463.3=109677\times 16(\frac{1}{n_1^2} -\frac{1}{5^2})\\n_1=4](https://tex.z-dn.net/?f=39463.3%3D109677%5Ctimes%204%5E2%28%5Cfrac%7B1%7D%7Bn_1%5E2%7D%20-%5Cfrac%7B1%7D%7B5%5E2%7D%29%5C%5C39463.3%3D109677%5Ctimes%2016%28%5Cfrac%7B1%7D%7Bn_1%5E2%7D%20-%5Cfrac%7B1%7D%7B5%5E2%7D%29%5C%5Cn_1%3D4)
Therefore, the principal quantum number corresponding to the given emission is 4.
1 has a higher ionization dismal aoa
Hey
Sorry, But There Is No 7th Element in group two. only six which is Radium.
~Spades15
Answer:
<u>ATGGCCTA</u>
Explanation:
For this we have to keep in mind that we have a <u>specific relationship between the nitrogen bases</u>:
-) <u>When we have a T (thymine) we will have a bond with A (adenine) and viceversa</u>.
-) <u>When we have C (Cytosine) we will have a bond with G (Guanine) and viceversa</u>.
Therefore if we have: TACCGGAT. We have to put the corresponding nitrogen base, so:
TACCGGAT
<u>ATGGCCTA</u>
<u></u>
I hope it helps!
An example is when on a seesaw if a kid is on one side and an adult is on the other then it is unbalanced because the adult weighs more