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Elanso [62]
2 years ago
11

How does the altitude of the Sun change throughout the year in Reno, NV?

Chemistry
1 answer:
vampirchik [111]2 years ago
5 0

Given what we know, we can confirm that in Reno, NV, the angle of the Sun is lower during the winter months and <u>higher </u>in the <u>sky </u>during the summer.

<h3>How can we know this?</h3>

We can know this about Reno, NV, given that it is irrelevant where we placed this question. the answer will be the same all across the world. It has to do with the way the Earth orbits the Sun as well as the tilt of the Earth. This causes the Sun to be higher in the sky during summer and lower in the winter months.

Therefore, we can confirm that the angle of the Sun is lower during the winter months and higher in the sky during the summer, both in Reno, NV and everywhere else.

To learn more about The Earth's orbit visit:

brainly.com/question/15022652?referrer=searchResults

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If the pressure on a 1.04 L sample of gas is doubled at constant temperature, please compute the new volume of gas: __
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Answer:

0.52 L.

Explanation:

Let P be the initial pressure.

From the question given above, the following data were obtained:

Initial pressure (P1) = P

Initial volume (V1) = 1.04 L

Final pressure (P2) = double the initial pressure = 2P

Final volume (V2) =?

The new volume (V2) of the gas can be obtained by using the the Boyle's law equation as shown below:

P1V1 = P2V2

P × 1.04 = 2P × V2

1.04P = 2P × V2

Divide both side by 2P

V2 = 1.04P /2P

V2 = 0.52 L

Thus, the new volume of the gas is 0.52 L.

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Lipids (also known as fats) have two types of monomers called
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Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, th
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Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

\text{Concentration of NO}=\frac{\text{Moles of }NO}{\text{Volume of solution}}=\frac{0.3152mol}{2.0L}=0.1576M

The given equilibrium reaction is,

                           N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

Initially conc.      0        0           0.1576

At eqm.               (x)       (x)        (0.1576-2x)

The expression of K_c will be,

K_c=\frac{[NO]^2}{[N_2][O_2]}

0.0153=\frac{(0.1576-2x)^2}{(x)\times (x)}

By solving the term, we get:

x=0.0742,0.0839

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

Now we have to calculate the equilibrium concentration of NO.

Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M

Therefore, the equilibrium concentration of NO is, 0.0092 M.

5 0
3 years ago
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Answer:

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