Answer:
The distance from the top of the stick would be 2l/3
Explanation:
Let the impulse 'FΔt' acts as a distance 'x' from the hinge 'H'. Assume no impulsive reaction is generated at 'H'. Let the angular velocity of the rod about 'H' just after the applied impulse be 'W'. Also consider that the center of percussion is the point on a bean attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.
Applying impulse momentum theorem for linear momentum.
FΔt = m(Wl/2), since velocity of center of mass of rod = Wl/2
Similarly applying impulse momentum theorem per angular momentum about H
FΔt * x = I * W
Where FΔt * x represents the impulsive torque and I is the moment of inertia
F Δt.x = (ml² . W)/3
Substituting FΔt
M(Wl/2) * x = (ml². W)/3
1/x = 3/2l
x = 2l/3
For the object that has a horizontal velocity component of 6 m/s and a vertical velocity component of 4 m/s we have:
1. The velocity of the object is 7.21 m/s.
2. The angle it makes with the horizontal is 33.7°.
1. The velocity of the object can be found as follows:
Where:
: is the horizontal component of the velocity = 6 m/s
: is the vertical component of the velocity = 4 m/s
Hence, the <u>velocity is</u>:
2. The angle it makes with the <u>horizontal </u>can be calculated with the following trigonometric function:
Where:
θ: is the angle it makes with the horizontal
Therefore, the <u>angle is</u>:
You can learn more about the components of the velocity here: brainly.com/question/2285233?referrer=searchResults
I hope it helps you!
The, it's electron goes for HIGHER orbital form lower orbital
Answer:
35 N to the right.
Explanation:
450 is going to the right so you subtract what is going against it. Which gives you 35. And because 450 is bigger than 415, it'll be going to the right.
Answer:
585lb
Explanation:
Given the following
F1 = 235lb
F2 = 350lb
The resultant is expressed as;
FR = F1+F2
Substitute the given values
FR = 235+350
FR = 585lb
Hence the magnitude of the resultant is 585lb
