Block A with mass mA=4.6 kg lies on a frictionless incline plane. It is connected by a massless rope over a frictionless, massle
ss pulley to block B with mass mB=6.4 kg. The plane is inclined at an angle of θ = 53.9°. The blocks are released from rest and block B falls a distance L=2.9 m. Find the speed of block B (v) when it has fallen a distance L, and the total kinetic energy (K) of the two blocks at that instant.
1 answer:
Answer:
Check the explanation
Explanation:
In calculate kinetic energy, write out a formula whereby the kinetic energy will be equal to 0.5 times mass times velocity squared. include in the value for the object mass, then the velocity with which it is moving.
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Answer:
The vapor pressure at 60.6°C is 330.89 mmHg
Explanation:
Applying Clausius Clapeyron Equation
Where;
P₂ is the final vapor pressure of benzene = ?
P₁ is the initial vapor pressure of benzene = 40.1 mmHg
T₂ is the final temperature of benzene = 60.6°C = 333.6 K
T₁ is the initial temperature of benzene = 7.6°C = 280.6 K
ΔH is the molar heat of vaporization of benzene = 31.0 kJ/mol
R is gas rate = 8.314 J/mol.k
Therefore, the vapor pressure at 60.6°C is 330.89 mmHg