Block A with mass mA=4.6 kg lies on a frictionless incline plane. It is connected by a massless rope over a frictionless, massle
ss pulley to block B with mass mB=6.4 kg. The plane is inclined at an angle of θ = 53.9°. The blocks are released from rest and block B falls a distance L=2.9 m. Find the speed of block B (v) when it has fallen a distance L, and the total kinetic energy (K) of the two blocks at that instant.
1 answer:
Answer:
Check the explanation
Explanation:
In calculate kinetic energy, write out a formula whereby the kinetic energy will be equal to 0.5 times mass times velocity squared. include in the value for the object mass, then the velocity with which it is moving.
Kindly check the attached image below to get the step by step explanation to the question above.
You might be interested in
Answer:
Explanation:
The apparent brightness follows an inverse square law, therefore we can write:
where I is the apparent brightness and r is the distance from the Sun.
We can also rewrite the law as
(1)
where in this problem, we have:
apparent brightness at a distance
, where
million km
We want to estimate the apparent brightness at , where
is ten times
, so
Re-arranging eq.(1), we find :