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AfilCa [17]
3 years ago
5

How does the force exerted by two magnets change as the magnets are moved farther apart?

Physics
1 answer:
galben [10]3 years ago
8 0
<span>The magnetic force exerted by two magnets decreases as the magnets are moved farther apart.

</span><span>The magnetic force between two magnets is the force of repulsion or attraction between two magnets which leads to the calculation of a positive work.
</span><span>The magnetic of a magnet is strongest at its poles.</span>
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The path of a meteor passing Earth is affected by its gravitational force and falls to Earth's surface. Another meteor of the sa
Lina20 [59]

Answer: The correct answer is option (C).

Explanation:

As it is given in the problem, the path of a meteor passing Earth is affected by its gravitational force and falls to Earth's surface. Another meteor of the same mass falls to Jupiter's surface due to its gravitational force.

According to Newton's law of universal gravitational, every particle attracts every other particles in the universe with the gravitational force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The Jupiter is the most massive planet in the solar system. It is also the largest planet in the solar system. The gravity of Jupiter on its surface is 2.4 times that of surface gravity of the Earth.

If a person weighs 100 pounds on the Earth then he would weigh 240 pounds on Jupiter.

Therefore, the correct answer is option (C), the meteor falls to Jupiter faster due to its greater gravitational force.

8 0
3 years ago
Read 2 more answers
⦁ A 68 kg crate is dragged across a floor by pulling on a rope attached to the crate and inclined 15° above the horizontal. (a)
GREYUIT [131]

Answer:

303.29N and 1.44m/s^2

Explanation:

Make sure to label each vector with none, mg, fk, a, FN or T

Given

Mass m = 68.0 kg

Angle θ = 15.0°

g = 9.8m/s^2

Coefficient of static friction μs = 0.50

Coefficient of kinetic friction μk =0.35

Solution

Vertically

N = mg - Fsinθ

Horizontally

Fs = F cos θ

μsN = Fcos θ

μs( mg- Fsinθ) = Fcos θ

μsmg - μsFsinθ = Fcos θ

μsmg = Fcos θ + μsFsinθ

F = μsmg/ cos θ + μs sinθ

F = 0.5×68×9.8/cos 15×0.5×sin15

F = 332.2/0.9659+0.5×0.2588

F =332.2/1.0953

F = 303.29N

Fnet = F - Fk

ma = F - μkN

a = F - μk( mg - Fsinθ)

a = 303.29 - 0.35(68.0 * 9.8- 303.29*sin15)/68.0

303.29-0.35( 666.4 - 303.29*0.2588)/68.0

303.29-0.35(666.4-78.491)/68.0

303.29-0.35(587.90)/68.0

(303.29-205.45)/68.0

97.83/68.0

a = 1.438m/s^2

a = 1.44m/s^2

7 0
3 years ago
What instrument can be used to show the shape of a sound wave?
mafiozo [28]
"Oscilloscope"  can be used to show the shape of a sound wave

Hope this helps!
7 0
3 years ago
An apple contains 165 Calories. How many actual calories does it contain? How many joules does it contain
jasenka [17]

Answer:

95 calories

Explanation:

A medium-sized apple has only 95 calories but plenty of water and fiber.

8 0
2 years ago
1. A listener stands 20.0 m from a speaker that pumps out music with a power output of 100.0 W.
marta [7]

(1.a) The surface area being vibrated by the time the sound reaches the listener is 5,026.55 m².

(1.b) The intensity of the sound wave as it reaches the person listening is 0.02 W/m².

(1.c) The relative intensity of the sound as heard by the listener is 103 dB.

(2.a) The speed of sound if the air temperature is 15⁰C is 340.3 m/s.

(2.b) The frequency of the sound heard by the suspect is 614.3 Hz.

<h3>Surface area being vibrated</h3>

The surface area being vibrated by the time the sound reaches the listener is calculated as follows;

A = 4πr²

A = 4π x (20)²

A = 5,026.55 m²

<h3>Intensity of the sound</h3>

The intensity of the sound is calculated as follows;

I = P/A

I = (100) / (5,026.55)

I = 0.02 W/m²

<h3>Relative intensity of the sound</h3>

B = 10log(\frac{I}{I_0} )\\\\B = 10 \times log(\frac{0.02}{10^{-12}} )\\\\B = 103 \ dB

<h3>Speed of sound at the given temperature</h3>

v= 331.3\sqrt{1 + \frac{T}{273} } \\\\v = 331.3\sqrt{1 + \frac{15}{273} } \\\\v = 340.3 \ m/s

<h3>Frequency of the sound</h3>

The frequency of the sound heard is determined by applying Doppler effect.

f_o = f_s(\frac{v \pm v_0}{v \pm v_s} )

where;

  • -v₀ is velocity of the observer moving away from the source
  • -vs is the velocity of the source moving towards the observer
  • fs is the source frequency
  • fo is the observed frequency
  • v is speed of sound

f_0 = f_s(\frac{v-v_0}{v- v_s} )

f_0 = 512(\frac{340.3 - 10}{340.3 - 65} )\\\\f_0 = 614.3 \ Hz

Learn more about intensity of sound here: brainly.com/question/17062836

3 0
1 year ago
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