Answer:
The average induced emf in the loop is 0.20 V
Explanation:
Given:
Radius of loop 
m
Magnetic field 
T
Change in time 
sec
According to the faraday's law,
Induced emf is given by
Where 
magnetic flux
( here 
)
Where 
We neglect minus sign because it's shows lenz law
V
Therefore, the average induced emf in the loop is 0.20 V
Answer:
The power output of this engine is 
The the maximum (Carnot) efficiency is 
The actual efficiency of this engine is 
Explanation:
From the question we are told that
The temperature of the hot reservoir is 
The temperature of the cold reservoir is 
The energy absorbed from the hot reservoir is 
The energy exhausts into cold reservoir is 
The power output is mathematically represented as
Where t is the time taken which we will assume to be 1 hour = 3600 s
W is the workdone which is mathematically represented as
substituting values
So
The Carnot efficiency is mathematically represented as
The actual efficiency is mathematically represented as
substituting values
Answer:
Pressure = 9.94 x 10⁶ Pascals
Explanation:
given data
mass = 51 kg
radius = 0.400 cm
solution
we know Pressure that is express as here
Pressure = total force on an area ÷ the area of the area .................1
and
Force is the woman's weight so weight will be
Weight = mass × gravity .................2
put here value
Weight = 51 × 9.8 m/s²
Weight = 499.8 Newtons
and
Area of a circle of bottom of the heel = (π) × (radius)² ...................3
put here value
Area = (π) × (0.40 cm)²
Area = 0.502654 cm²
Area = 0.0000502654 m²
and
now we put value in equation 1 we get
Pressure = force ÷ area
Pressure = 499.8 ÷ 0.0000502654
Pressure = 9943221.381 N/m²
Pressure = 9.94 x 10⁶ Pascals
I included things
Hope this helps!
Answer:
0.36 A.
Explanation:
We'll begin by calculating the equivalent resistance between 35 Ω and 20 Ω resistor. This is illustrated below:
Resistor 1 (R₁) = 35 Ω
Resistor 2 (R₂) = 20 Ω
Equivalent Resistance (Rₑq) =?
Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:
Rₑq = (R₁ × R₂) / (R₁ + R₂)
Rₑq = (35 × 20) / (35 + 20)
Rₑq = 700 / 55
Rₑq = 12.73 Ω
Next, we shall determine the total resistance in the circuit. This can be obtained as follow:
Equivalent resistance between 35 Ω and 20 Ω (Rₑq) = 12.73 Ω
Resistor 3 (R₃) = 15 Ω
Total resistance (R) in the circuit =?
R = Rₑq + R₃ (they are in series connection)
R = 12.73 + 15
R = 27.73 Ω
Finally, we shall determine the current. This can be obtained as follow:
Total resistance (R) = 27.73 Ω
Voltage (V) = 10 V
Current (I) =?
V = IR
10 = I × 27.73
Divide both side by 27.73
I = 10 / 27.73
I = 0.36 A
Therefore, the current is 0.36 A.
