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2 years ago

Among at most how many coins can you find the “light one” if you are permitted to use the scale only twice? Only three times?

Mathematics

1 answer:

nadya68 [22]2 years ago

7 0

Answer:

So in two weighings, we can find a single light coin from a set of 3 × 3 = 9. By extension, it would take only three weighings to find the odd light coin among 27 coins, and four weighings to find it from 81 coins.

Step-by-step explanation:

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Mark has a yard in the shape shown the area of his yard is 100 square meters the bottom side (base) is 20 meters what is the dis

vesna_86 [32]

Answer:

5 meters

Step-by-step explanation:

because 100 meters divided by the base equals the Height so 100 divided by 20 = 5

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2 years ago

21% of deaths among male adults can be attributed to heart diseases. Is this percentage different among residents in Sonoma Coun

qwelly [4]

Answer:

Step-by-step explanation:

The null hypothesis is usually the default statement while the alternative hypothesis is its opposite and usually tested against the null hypothesis.

In this case study, the null hypothesis is u = 21%/0.21, the percentage is not different among residents in Sonoma County and is equal to 0.21.

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2 years ago

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irinina [24]

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2 years ago

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How to solve combing functions<br> Do I do this pls help

Over [174]

Answer:

3x - 2

Step-by-step explanation:

f(x) + g(x)

sub in functions

2x + 1 + x - 3

combine

3x -2

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2 years ago

Lydia graphed ADEF at the coordinates D (-2,-1), E (-2, 2), and F (0,0). She thinks ADEF is a right triangle. Is Lydia's asserti

Setler79 [48]

The true statement is (c) No; the slopes of segment EF and segment DF are not opposite reciprocals.

<h3>Right triangles </h3>

Right triangles have a pair of perpendicular lines

Coordinates

The coordinates are given as:

D = (-2,-1)
E = (-2,2)
F = (0,0)

<h3>Slopes</h3>

Start by calculating the slopes of lines DF and EF using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$m_{DF} = \frac{0 + 1}{0 +2}$

$m_{DF} = \frac{1}{2}$

Also, we have:

$m_{EF} = \frac{0 -2 }{0+2}$

$m_{EF} = \frac{-2 }{2}$

$m_{EF} = -1$

For the triangle to be a right triangle, then the calculated slopes must be opposite reciprocals.

i.e.

$m_1 = -\frac{1}{m_2}$

By comparison, the slopes of both lines are not opposite reciprocals.

Hence, the true statement is (c)