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Oduvanchick [21]
3 years ago
11

PLEASE HELP FAST!!!! ITEM BANK: Move to Bottom

Physics
1 answer:
kkurt [141]3 years ago
6 0

Answer:

WHat ?????

Explanation:

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Give 4 examples of chemical weathering.
Ulleksa [173]

Answer:

Explanation:

Carbonation. When you think of carbonation, think carbon! ...

Oxidation. Oxygen causes oxidation. ...

Hydration. This isn't the hydration used in your body, but it's similar. ...

Hydrolysis. Water can add to a material to make a new material, or it can dissolve a material to change it. ...

Acidification.

7 0
3 years ago
The Big Bang Theory is a theory about the expansion of the universe. True False
tatuchka [14]
The Big Bang Theory is a theory about the expansion of the universe.

The answer is True
8 0
3 years ago
What is the approximate horizontal velocity at which the boy in the diagram
4vir4ik [10]

Answer:

D

Explanation:

5+25=30

7 0
3 years ago
A soccer ball kicked on a level field has an initial vertical velocity component of 15.0 mps. assuming the ball lands at the sam
telo118 [61]

Answer:

The time taken for the ball to fly up in the air and back down again is 3.058 seconds.

Explanation:

Since the ball ends up at the same vertical distance ( on the ground) as it was at the start of its motion, we can set the total displacement of the ball equal to 0.

Thus, this problem can be simply solved by the following equation of motion:

s = u*t + \frac{1}{2} (a*t^2)

Here, s = total change in distance = 0 m

u = initial speed = 15 m/s

a = acceleration due to gravity = -9.81 m/s^2

t = time (to be found)

Substituting these values in the equation we get:

0=15t+0.5(-9.81t^2)

-15t = -4.905t^2

t=15/4.905

t = 3.058 seconds

So, the time taken for the ball to fly up in the air and back down again is 3.058 seconds.

5 0
3 years ago
4.A guitar player is deliberately trying to produce beats by bending one string to make it almost match another unbent string’s
mr Goodwill [35]

When two sound sources of the same amplitude and similar frequencies f₁ and f₂ are played at a time, beats are produced with a frequency given by:

f_{beat}=|f_2-f_1|

Since the guitar player wants to hear 9 beats in 2 seconds, then:

f_{beat}=\frac{9}{2s}=4.5Hz

Then, the pitches that can be used are those whose difference with respect to the frequency of 343Hz is 4.5Hz:

\begin{gathered} f_2=f_1\pm f_{beat} \\  \\ \Rightarrow f_2=343Hz\pm4.5Hz \\  \\ \therefore f_{2,1}=347.5Hz \\ f_{2,2}=338.5Hz \end{gathered}

Therefore, the pitches he could bend the string to, are 347.5Hz and 338.5Hz.

7 0
1 year ago
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