Answer:
"a certain compact disc (CD) contains 783.216 megabytes of digital information 4"
Answer:
HP = 27.08 hp
Explanation:
The complete question has a theoretical flow rate of 18.2 GPM. So, to find the input horsepower, we will use the following formula:
HP = QP/1714(E)
where,
HP = Input Horse Power = ?
Q = Volume Flow Rate in Gallons Per Minute (GPM) = 18.2 GPM
P = Outlet Pressure in psi = 2372 psi
E = Mechanical Efficiency = 0.93
Therefore,
HP = (18.2 GPM)(2372 psi)/(1714)(0.93)
<u>HP = 27.08 hp</u>
Answer:
a) 250 N/m
b) 22.4 rad/s , 3.6 Hz , 0.28 sec
c) 0.3125 J
Explanation:
a)
F = force applied on the spring = 7.50 N
x = stretch of the spring from relaxed length when force "F" is applied = 3 cm = 0.03 m
k = spring constant of the spring
Since the force applied causes the spring to stretch
F = k x
7.50 = k (0.03)
k = 250 N/m
b)
m = mass of the particle attached to the spring = 0.500 kg
Angular frequency of motion is given as


= 22.4 rad/s
= frequency
Angular frequency is also given as
= 2 π
22.4 = 2 (3.14) f
= 3.6 Hz
= Time period
Time period is given as


= 0.28 sec
c)
A = amplitude of motion = 5 cm = 0.05 m
Total energy of the spring-block system is given as
U = (0.5) k A²
U = (0.5) (250) (0.05)²
U = 0.3125 J
Answer: The shortest possible wavelength of sound the organ can produce is 0.224 m
Explanation:
To calculate the wavelength of light, we use the equation:

where,
= wavelength of the light
c = speed of light = 
As wavelength and frequency follows inverse relation, shortest wavelength is produced by highest frequency.
= highest frequency of light =


Thus the shortest possible wavelength of sound the organ can produce is 0.224 m