R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3
HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
=-20/8
=-2.5
Isostasy is the concept used to explain the dynamics of the earth's upper layers. It is considered that there is a gravitational equilibrium that exists between the earth's upper most layer, the crust, and the next layer, the mantle. The crust is said to "float" on the mantle.
Therefore, in this model, the block of wood represents the crust and the water represents the earth's mantle.
Explanation:
Given that,
Initial velocity, u = 11.3 m/s
Angle above the horizontal,
Time of flight :
Horizontal distance traveled is given by :
x = ut
x = 11.3 m/s × 1.32 s
x = 14.916 m
Maximum height is given by :
Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.
Answer: a stone thrown into a lake
Explanation:
The option that exhibits parabolic motion is a stone that is thrown into a lake.
Projectile motion is a form of motion that is seen when a particular object is thrown towards the surface fo the Earth. Such objects are acted upon by gravity.
(a) When the spring is compressed 4.5 cm = 0.045 m, it exerts a restoring force on the block of magnitude
<em>F</em> = (1900 N/m) (0.045 m) = 85.5 N
so that at the moment the block is released, this force accelerates the block with magnitude <em>a</em> such that
85.5 N = (1.15 kg) <em>a</em> ==> <em>a</em> = (85.5 N) / (1.15 kg) ≈ 74.3 m/s²
The block reaches its maximum speed at the spring's equilbrium point, and this speed <em>v</em> is such that
<em>v</em> ² = 2 (74.3 m/s²) (0.045 m) ==> <em>v</em> = √(2 (74.3 m/s²) (0.045 m)) ≈ 2.59 m/s
(b) There is no friction between the block and plane, so the block maintains this speed as it slides over the edge. At that point, it's essentially in free fall, so if <em>y</em> is the height of the plane, then
(7 m/s)² - (2.59 m/s)² = 2<em>gy</em> ==> <em>y</em> = ((7 m/s)² - (2.59 m/s)²) / (2<em>g</em>) ≈ 2.16 m