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Advocard [28]
3 years ago
8

Which best describes the surface of a concave mirror? It is flat. It is textured. It curves outward. It curves inward.

Physics
1 answer:
Sonja [21]3 years ago
8 0

The concave mirror is a spherical-shaped mirror that has an inner curved surface. Hence, option (4) is correct.

What is a concave mirror?

The concave mirrors are spherical-shaped mirrors that are painted on the outward surface. It is also known as the converging mirror, having the recessed inner reflecting surface.

  • The concave mirrors are generally used for the purpose to focus the light. For that, they might have a reflecting surface, curved inwards, and the reflection of light is limited to the single focal point.
  • The reflecting surface of the concave mirror has its vertex or midpoint lying farther away from the objects than the edges.

Thus, we can conclude that the surface of the concave mirror is curved inward. Hence, option (4) is correct.

Learn more about the concave mirror here:

brainly.com/question/13300307

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An object with a mass of 1.5 kg changes its velocity +15 m/s during a time interval of 3.5 seconds what impulse was delivered to
Arada [10]
The answer is 10.5 kg m/s

Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt

Force (F) is the multiplication of mass (m) and acceleration (a): F = m · a

Acceleration (a) can be expressed as change in velocity (v) divided by time interval (Δt): a = Δv/Δt

So: 
a = Δv/Δt         ⇒ F = m · a = m · Δv/Δt
F = m · Δv/Δt   ⇒ I = m · Δv/Δt · Δt
Since Δt can be cancelled out, impulse can be expressed as:
I = m · Δv = m · (v2 - v1)

It is given:
m = 1.5 kg
v1 = 15 m/s
v2 = 22 m/s

I = 1.5 · (22 - 15) = 1.5 · 7 = 10.5 kgm/s.
7 0
4 years ago
How much power is used if an athlete lifts a 50N weight up 2 meters in 10 seconds?
Tcecarenko [31]

Answer:

the power used by the person is 10 W.

Explanation:

Given;

weight lifted, W = 50 N

distance through which the weight was lifted, d = 2 m

time of motion, t = 10 s

The power used by the person is calculated as;

P= FV\\\\P = F \ \times \ \frac{d}{t} \\\\P = 50 \ \times \ \frac{2}{10} \\\\P = 10 \ W

Therefore, the power used by the person is 10 W.

3 0
4 years ago
10^-1 phones in microphones
Arada [10]
1 microphone = (presumably)  10⁻⁶ phone

1 phone = (presumably)  10⁶  microphones

(10⁻¹) phone  =  (presumably)  (10⁻¹) x (10⁶ microphones)

                       =       10⁵ microphones.
4 0
3 years ago
A chair of weight 70.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F =
Annette [7]

Answer:

94.67 N

Explanation:

Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.

At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.  

\begin{array}{l}\\\Sigma {F_y} = 0\\\\N - W - F\sin \theta = 0\\\\N = W + F\sin \theta \\\end{array}

Substituting 70 N for W, 41 N for F and \theta for 37 degrees

N=70+41sin37=94.67441595  N and rounding off to 2 decimal places

N=94.67 N

​

6 0
4 years ago
If the Moon's orbit were perpendicular to the ecliptic, would eclipses be possible? What would be the most common phase of the M
tangare [24]

Answer:no

Explanation:

5 0
4 years ago
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