The answer is 10.5 kg m/s
Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt
Force (F) is the multiplication of mass (m) and acceleration (a): F = m · a
Acceleration (a) can be expressed as change in velocity (v) divided by time interval (Δt): a = Δv/Δt
So:
a = Δv/Δt ⇒ F = m · a = m · Δv/Δt
F = m · Δv/Δt ⇒ I = m · Δv/Δt · Δt
Since Δt can be cancelled out, impulse can be expressed as:
I = m · Δv = m · (v2 - v1)
It is given:
m = 1.5 kg
v1 = 15 m/s
v2 = 22 m/s
I = 1.5 · (22 - 15) = 1.5 · 7 = 10.5 kgm/s.
Answer:
the power used by the person is 10 W.
Explanation:
Given;
weight lifted, W = 50 N
distance through which the weight was lifted, d = 2 m
time of motion, t = 10 s
The power used by the person is calculated as;

Therefore, the power used by the person is 10 W.
1 microphone = (presumably) 10⁻⁶ phone
1 phone = (presumably) 10⁶ microphones
(10⁻¹) phone = (presumably) (10⁻¹) x (10⁶ microphones)
= 10⁵ microphones.
Answer:
94.67 N
Explanation:
Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.
At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.

Substituting 70 N for W, 41 N for F and
for 37 degrees
N=70+41sin37=94.67441595 N and rounding off to 2 decimal places
N=94.67 N