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Alborosie
2 years ago
10

Write the balanced chemical equation for the combustion of sodium metal

Chemistry
1 answer:
zhannawk [14.2K]2 years ago
8 0

Answer:

sodium appears as a silvery soft metal that becomes grayish white upon exposure to air

Explanation:

molecular weight 22.989769 g/mol

modify dates 2021 -01-23

create dates 2004-09-16

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Which statement is always true of the cathode in an electrochemical cell? Reduction occurs here. It is considered the "negative"
lara31 [8.8K]

Answer:

It Is Considered The "negative" Electrode

Explanation:

An electrochemical cell is an electrolytic cell that drives a non-spontaneous redox reaction through the application of electrical energy. This cell is used to decompose chemical compounds, in a process called electrolysis. An electrode at which reduction take place is called the cathode. In reduction, electrons travel toward the site of reduction such that the negative charge is on the cathode.

7 0
2 years ago
4. What is the difference between an open system and a<br> closed system?
Nimfa-mama [501]

Systems can exist in three ways as open systems, closed systems, and isolated systems. The main difference between open and closed system is that in an open system, matter can be exchanged with the surrounding whereas, in a closed system, matter cannot be exchanged with the surrounding.

btw why not just look it up on google? btw btw brainliest plz

5 0
3 years ago
If 200 ml of 0.15 M propionic acid (PA) is added to 300 ml of 0.02 M NaOH, what is the resulting pH of the solution? Round the a
vodomira [7]

Answer:

pH = 4.543

Explanation:

  • CH3CH2COOH  + H2O ↔ CH3CH2COO-  +  H3O+
  • pKa = - Log Ka

∴ Ka = [H3O+][CH3CH2COO-]/[CH3CH2COOH]

∴ pKa = 4.87

⇒ Ka = 1.349 E-5 = [H3O+][CH3CH2COO-]/[CH3CH2COOH]

added 300 mL 0f 0.02 M NaOH:

⇒ <em>C</em> CH3CH2COOH = ((0.200 L)(0.15 M)) - ((0.300 L)(0.02 M))/(0.3 + 0.2)

⇒ <em>C</em> CH3CH2COOH = 0.048 M

⇒ <em>C</em> NaOH = (0.300 L)(0.02 M) / (0.3 +0.2) = 0.012 M

mass balance:

⇒ 0.048 + 0.012 = 0.06 M = [CH3CH2COO-] + [CH3CH2COOH].......(1)

charge balance:

⇒ [H3O+] + [Na+] = [CH3CH2COO-]

∴ [Na+] = 0.02 M

⇒ [CH3CH2COO-] = [H3O+] + 0.02 M.............(2)

(2) in (1):

⇒ [CH3CH2COOH] = 0.06 M - 0.02 M - [H3O+] = 0.04 M - [H3O+]

replacing in Ka:

⇒ 1.349 E-5 = [H3O+][([H3O+] + 0.02) / (0.04 - [H3O+])

⇒ (1.349 E-5)(0.04 - [H3O+]) = [H3O+]² + 0.02[H3O+]

⇒ 5.396 E-7 - 1.349 E-5[H3O+] = [H3O+]² + 0.02[H3O+]

⇒ [H3O+]² + 0.02001[H3O+] - 5.396 E-7 = 0

⇒ [H3O+ ] = 2.867 E-5 M

∴ pH = - Log [H3O+]

⇒ pH = 4.543

3 0
3 years ago
you have an object with mass of 86 g and volume of 10 cm^3 (cubed). calculate density, show your work, and identify which materi
sleet_krkn [62]

Answer:

8.6g/cm³ (BRASS)

Explanation:

Given the following :

Mass of object = 86g

Volume of object = 10cm³

The density of an object is calculated using the formula :

Density(g/cm³) = mass(g) / volume(cm³)

Inputting our values :

Density = 86g / 10cm³

Density = 8.6g/cm³

According to the table provided, the object which corresponds to having a density of 8.6g/cm³ is BRASS

6 0
3 years ago
A lab experiment shows: merge a litmus paper in a
ddd [48]

Answer:

2.

Explanation:

When you put the paper in a solution, it will turn blue if it is basic, or red if it is acidic. If it does not change color, it is fairly neutral.

6 0
3 years ago
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