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3 years ago

98 POINTS! MUST SHOW YOUR WORK for Brainliest!

Chemistry

2 answers:

Ede4ka [16]3 years ago

7 0

Nickel (II) chloride has the chemical formula of NiCl2. So 1 mole of NiCl2 contains 1 mole of Ni atoms.

1 mole contains 6.02*10^23 atoms. So 100 moles of Nickel (II) chloride contains 6.02*10^25 Ni atoms.

Annette [7]3 years ago

5 0

1 mole has 6.02*10^23 molecules in it.

1 nickel (II) chloride molecule, NiCl2, has 1 Ni atom in it.

so 1 mole of nickel (II) chloride molecule has 1 mole of Ni atom in it.

so 100 moles of nickel (II) chloride molecule has 100*6.02*10^23

= 6.02*10^25 Ni atom in it.

You might be interested in

A chemist wants to make 6.5 L of a 0.340 M CaCl2 solution. Part A What mass of CaCl2 (in g) should the chemist use? Express your

katovenus [111]

Answer:

The answer to your question is 245 grams

Explanation:

Data

Volume 6.5 L

Molarity = 0.34

mass of CaCl₂ = ?

Process

1.- Calculate the molar mass of CaCl₂

molar mass = (1 x 40) + (2 x 35.5)

= 40 + 71

= 111 g

2.- Convert the grams to moles

111 g of CaCl₂ -------------- 1 mol

x ---------------0.34 mol

x = (0.34 x 111) / 1

x = 37.74 g

3.- Calculate the total mass

37.74 g ------------------ 1 L

x ------------------ 6.5 L

x = (6.5 x 37.74) / 1

x = 245.31

3 0

3 years ago

Use the following equation to answer the questions below:

Gala2k [10]

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

What is the mass of beryllium required to produce 25.0g of beryllium chloride?

1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass * Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

Mass = 0.6256 * 36.5 = 22.83 g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

25g of BeCl2 = 0.3128 mol of BeCl2

From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

Mass = Number of moles * Molar mass

Mass = 0.3128mol * 2.0159 g/mol = 0.6306 g

3 0

3 years ago

What would be the major product obtained from hydroboration–oxidation of the following alkenes?

zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore the "OH" will be added to carbon 2 producing 2-methylcyclohexan-1-ol.

See figure 1

I hope it helps!