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2 years ago

An aluminum soft drink can is approximately 0.55 moles of aluminum. How many

Chemistry

1 answer:

Morgarella [4.7K]2 years ago

3 0

Explanation:

Round 87.073 meters to 3 significant figures. write your answer in scientific notation. step 1: 87.073 rounds to step 2: write scientific notation : meters...

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The following list contains some common radicals. Using the charges on these ions and the idea of valence, predict the formulas

lesantik [10]

Answer : The formula for the compound sodium carbonate is $Na_2CO_3$

The formula for the compound potassium permanganate is $KMnO_4$

Explanation :

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non-metals.

(a) Sodium carbonate

In the compound, the sodium metal forms an ionic compound with polyatomic anion (carbonate) $CO_3^{2-}$ .

Here, sodium is having an oxidation state of +1 called as $Na^{1+}$ cation and carbonate $CO_3^{2-}$ is an anion with oxidation state of -2. The charges are not balanced. So, the charges are balanced by the cris-cross method. Thus, the compound formed will be, $Na_2CO_3$

Hence, the formula for the compound sodium carbonate is $Na_2CO_3$

(b) Potassium permanganate

In the compound, the potassium metal forms an ionic compound with polyatomic anion (permanganate) $MnO_4^{1-}$ .

Here, potassium is having an oxidation state of +1 called as $K^{1+}$ cation and permanganate $MnO_4^{1-}$ is an anion with oxidation state of -1. The charges are balanced. Thus, the compound formed will be, $KMnO_4$

Hence, the formula for the compound potassium permanganate is $KMnO_4$

3 0

3 years ago

How many grams of agcl would be needed to make a 4. 0 m solution with a volume of 0. 75 l?

devlian [24]

430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

<h3>What is Molarity?</h3>

The amount of a substance in a specific volume of solution is known as its molarity (M).

The number of moles of a solute per liter of a solution is known as molarity.

<h3>Calculation of Required amount of AgCl</h3>

Remember that mol/L is the unit of molarity (M).

We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.

0.75L×4.0M=3.0mol

Then, using the periodic table's molar mass for AgCl, convert from moles to grams:

3.0mol×143.321gmol=429.963g

The final step is to round to the correct significant figure, which in this case is two: 430g.

Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

Learn more about Molarity here:
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8 0

1 year ago

2CH3CHO+O2=> 2CH3COOH

Dovator [93]

Answer:

2CH3CHO + O2 → 2CH3COOH

7 0

2 years ago

You determine that Lauren's EER is 2200 kcal/day. You recommend and intake of 60% CHO, 15% protein, and 25% fat. Approximately h

const2013 [10]

Answer:

The answer to your question is 330 g of CHO

Explanation:

Data

Calories needed = 2200 kcal/day

CHO = 60%

Proteins = 15%

Fats = 25%

Grams of carbohydrates needed = ?

Process

1.- Calculate the number of calories in 60% of 2200 kcal

2200 kcal ---------------- 100%

x --------------- 60%

x = (60 x 2200) / 100

x = 1320 kcal

2.- Calculate the grams of CHO

1 g of CHO ---------------- 4 kcal

x ---------------- 1320 kcal

x = (1320 x 1) / 4

x = 1320/4

x = 330 g of CHO

6 0

3 years ago

A barium hydroxide solution is prepared by dissolving 1.90 g of Ba ( OH ) 2 in water to make 71.1 mL of solution. What is the co

goldenfox [79]

Answer:

The molarity of this solution is 0.156 M

Explanation:

Step 1: Data given

Mass of Ba(OH)2 = 1.90 grams

Molar mass Ba(OH)2 = 171.34 g/mol

Volume of the solution = 71.1 mL = 0.0711 L

Step 2: Calculate moles Ba(OH)2

Moles Ba(OH)2 = mass Ba(OH)2 / molar mass Ba(OH)2

Moles Ba(OH)2 = 1.90 grams / 171.34 g/mol

Moles Ba(OH)2 = 0.0111 moles

Step 3: Calculate molarity

Molarity solutin = moles Ba(OH)2 / volume solution

Molarity solution = 0.0111 moles / 0.0711 L

Molarity solution = 0.156 M

The molarity of this solution is 0.156 M

6 0

3 years ago