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solmaris [256]
4 years ago
11

the mass if an element is .007502 x 10^-26 g. find the Number of significant figures when the mass is converted to mg. (both mas

ses values have same order of magnitude)

Chemistry
1 answer:
andrezito [222]4 years ago
7 0

Answer:

d. 4.

Explanation:

Hello,

In this case, the required number on milligrams is:

0.007502x10^{-26}g*\frac{1000mg}{1g}=7.502x10^{-26}mg

It means that it has four significant figures which are counted for 7, 5, 0 and 2, considering that zero as it is to the right of first nonzero digit (7).

Regards.

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mihalych1998 [28]

<u>Answer:</u> The potential of the given cell is 1.551 V

<u>Explanation:</u>

The given chemical cell follows:

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E_{cell} = electrode potential of the cell = ? V

E^o_{cell} = standard electrode potential of the cell = +1.561 V

n = number of electrons exchanged = 2

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[Ag^{+}]=0.240M

Putting values in above equation, we get:

E_{cell}=1.561-\frac{0.059}{2}\times \log(\frac{(0.125)}{(0.240)^2})

E_{cell}=1.551V

Hence, the potential of the given cell is 1.551 V

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