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4 years ago

Definition of enthalpy

2 answers:

8 0

Thermodynamic quantity equivalent to the total heat content of a system It is equal to the internal energy of the system plus the product of pressure and volume

just olya [345]4 years ago

5 0

The definition for Thermodynamic is a quantity equivalent to the total heat content of a system It is equal to the internal energy of the system plus the product of pressure and volume. Hope it help!

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Bond formed by the sharing of electrons between atoms.

erica [24]

The bond formed between two or more electrons of different atoms is called a COVALENT BOND.

3 0

3 years ago

Read 2 more answers

a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill

baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

Also,

Moles = mass (m) / Molar mass (M)

Density (d) = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

$PM=dRT$

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0

3 years ago

How much is the oxygen valency?

Marina CMI [18]

The oxygen valency is 2

4 0

2 years ago

2Li + H2SO4=Li2SO4 + H2 How many liters of hydrogen gas, H2 at STP can be produced from 3.0 moles of Li? The molar volume of a g

Gemiola [76]

Answer:

volume of $H_2=33.6 litre$

Explanation:

Firstly balance the given chemical equation,

$2Li + H_2SO_4=Li_2SO_4 + H_2$

From the given balance equation it is clearly that,

2 mole of Li gives 1 mole of H2 gas

$2 mole Li$ ⇔ $1 mole H_2$

$1 mole Li$ ⇔ $0.5 mole H_2$

$3 mole Li$ ⇔ $1.5 mole H_2$

hence

3 mole of Li will give 1.5 mole H2 gas

therefore volume of gas produced from 3 mole Li at $STP = 1.5\times22.4 \frac{L}{mol}$

volume of H2=33.6 litre

7 0

3 years ago

What is the maximum amount of HCl, in grams, that can be produced if 37.5 g of BCl3 and 60.0 g of H2O are reacted according to t

Rus_ich [418]

Ooooh boy alright. So, this may or may not be a limited reactant problem so we need to first find out of it is.

First, how many moles of each substance are there

the molar mass of BCl3 is <span>117.17 grams so 37.5 g / 117.17 is ~ .32 mol.
The molar mass of H2O is 18.02 so 60 / 18.02 is ~ 3.33 mol.

Now, for every 1 mole of BCl3, there are 3 moles of HCl created. Therefore, BCl3 can create ~ .96 moles.
For every 3 moles of H2O, there are 3 moles of HCl created. Therefore, HCl can create ~3.33 moles.

But, there is not enough BCl3 to support that 3.33 moles, only enough for .96 moles, therefore BCl3 is the limiting reactant. Now, to answer the question, simply multiply .96 moles by the molar mass of HCl.

.96 x 36.46 = ~35 g</span>

6 0

3 years ago