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3 years ago

How can we use the balloon experiment to prove that air has weight (even though we cannot see air)?

Physics

2 answers:

Gala2k [10]3 years ago

7 0

Answer:

The end of the meter stick with the deflated balloon should have risen into the air. ... The only way the balloon could have lost mass is if the air that was inside it has mass. With this experiment you have shown that air takes up space and has mass, so you have proven that air is matter.

Explanation:

docker41 [41]3 years ago

3 0

Place an empty balloon on weighing machine, then fill it with air and place on weighing machine.

You will observe that air filled balloon has more weight than the empty balloon.

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A rocket moves through outer space at 11,000 m/s. At this rate, how much time would be required to travel the distance from Eart

Charra [1.4K]

11,000 m = 11 km

11 km/s over 380,000km

380,000 / 11 = 34545.4 seconds

34545.4 / 60 = 575.7 minutes

5 0

3 years ago

A feather is dropped on the moon from the height of 1.4m. The acceleration of gravity on the moon is 1.67ms-1. Determine the tim

Zinaida [17]

1.3s

Explanation:

Given parameters:

Height = 1.4m

Gravity on moon = 1.67ms⁻¹

Unknown:

Time for feather to fall = ?

Solution:

To solve this problem, we are going to use one of the motion equation that relates time, gravity and height.

H = ut + $\frac{1}{2} g t^{2}$

Sine the body was dropped from rest, initial velocity is zero;

H = height

u = initial velocity

t = time

g = acceleration due to gravity

since u = 0;

H = $\frac{1}{2} g t^{2}$

1.4 = $\frac{1}{2}$ x 1.67 x t²

t = 1.3s

learn more:

Gravity brainly.com/question/10934170

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8 0

3 years ago

A large fraction of the ultraviolet (UV) radiation coming from the sun is absorbed by the atmosphere. The main UV absorber in ou

elena55 [62]

Answer:

$3.2\times 10^{-7}\ m$ or 0.32 μm.

Explanation:

Given:

The radiations are UV radiation.

The frequency of the radiations absorbed (f) = $9.38\times 10^{14}\ Hz$

The wavelength of the radiations absorbed (λ) = ?

We know that, the speed of ultraviolet radiations is same as speed of light.

So, speed of UV radiation (v) = $3\times 10^8\ m/s$

Now, we also know that, the speed of the electromagnetic radiation is related to its frequency and wavelength and is given as:

$v=f\lambda$

Now, expressing the above equation in terms of wavelength 'λ', we have:

$\lambda=\frac{v}{f}$

Now, plug in the given values and solve for 'λ'. This gives,

$\lambda=\frac{3\times 10^8\ m/s}{9.38\times 10^{14}\ Hz}\\\\\lambda=3.2\times 10^{-7}\ m\\\\\lambda=3.2\times 10^{-7}\times 10^{6}\ \mu m\ [1\ m=10^6\ \mu m]\\\\\lambda=3.2\times 10^{-1}=0.32\ \mu m$