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3 years ago

How can we use the balloon experiment to prove that air has weight (even though we cannot see air)?

Physics

2 answers:

Gala2k [10]3 years ago

7 0

Answer:

The end of the meter stick with the deflated balloon should have risen into the air. ... The only way the balloon could have lost mass is if the air that was inside it has mass. With this experiment you have shown that air takes up space and has mass, so you have proven that air is matter.

Explanation:

docker41 [41]3 years ago

3 0

Place an empty balloon on weighing machine, then fill it with air and place on weighing machine.

You will observe that air filled balloon has more weight than the empty balloon.

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A LASIK vision-correction system uses a laser that emits 10-ns-long pulses of light, each with 3.0 mJ of energy. The laser beam

lyudmila [28]

<span>P = energy/t = 0.0025/1E-8 = 250000 W
I(ave) = P/A = 250000/(pi*0.425E-3^2) = 4.4056732E11 W/m^2
I(peak) = 2I(ave) = 8.8113463E11 W/m^2
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3 years ago

A soccer player kicks a ball at rest on the

scoundrel [369]

The kinetic energy and gravitational potential energy changes during its movement from ground to the top height.

<h3>What happens to kinetic and potential energy while motion?</h3>

When the ball moves upward, its gravitational potential energy is increases and kinetic energy begins to decrease but when the ball falls towards the earth, its gravitational potential energy is transformed into kinetic energy. When the ball collides with the ground, the kinetic energy is transformed into other forms of energy.

Learn more about kinetic energy here: brainly.com/question/20658056

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2 years ago

When enough ____ is added to the substance, the solid reaches its ____ point and becomes a liquid

Ratling [72]

Answer: When enough __energy__ is added to the substance, the solid reaches its _melting_ point and becomes a liquid

Explanation: since energy is being added the substance changes phase into a liquid .

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4 years ago

The mass of a planet is 3.7 x 1024 kg. If the planet has a radius of 9.2 x 106 m what is the acceleration of gravity for a perso

nalin [4]

Explanation:

It s given that,

Mass of a planet, $M=3.7\times 10^{24}\ kg$

Radius of a planet, $R=9.2\times 10^{6}\ m$

(1) We need to find the acceleration due to gravity for a person on the surface of the planet. Its formula is given by :

$g=\dfrac{GM}{R^2}$

$g=\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{(9.2\times 10^{6}\ m)^2}$

$g=2.91\ m/s^2$

(2) The escape velocity is given by :

$v=\sqrt{\dfrac{2GM}{R}}$

$v=\sqrt{{\dfrac{2\times 6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{9.2\times 10^{6}\ m}}$

v = 7324.61 m/s

Hence, this is the required solution.

3 0

3 years ago

I need help with part D

natka813 [3]

1). The little projectile is affected by friction all the way through the block.
Friction robs some kinetic energy.

2). The block is affected by friction as it scrapes along the top of the post.
Friction robs some kinetic energy.

3). The block is also affected by friction with the air (air resistance) as it
falls to the ground. Friction robs some kinetic energy.

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3 years ago