If two negative charges of -2 C and -2 C are put 32,692 m apart from each other how much force will push them apart?
1 answer:
Answer:
33.65 N
Explanation:
Force that will push them away is given from the equation;
F = Kq1•q2/r²
Where;
K is coulumbs constant = 8.99 × 10^(9) Nm²/C²
We are given;
q1 = q2 = -2 C
r = 32692 m
Thus;
F = 8.99 × 10^(9) × (-2) × (-2)/32692²
F ≈ 33.65 N
You might be interested in
The Battle of the Bulge in the winter of 1944 was the last Great German offensive of the Second World War.
Data was used from three different stations. Where their data overlapped was where the epicenter was located.
it is called triangulation
The amount of matter in an object is called its, mass. How much the mass weights would be referred to as weight
Answer:
(a): The resultant force acting on the object are F= (5.99 i + 14.98 j).
(b): The magnitude of the resultant force are F= 16.4 N < 68.19º .
Explanation:
m= 3kg
a= 2 i + 5 j = 5 .38 < 68.19 º
F= m * a
F= 3* ( 5.38 < 68.19º )
F= 16.4 N < 68.19º
Fx= F * cos(68.19º)
Fx= 5.99
Fy= F* sin(68.19º)
Fy= 14.98
