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FinnZ [79.3K]
3 years ago
6

Question #4

Physics
2 answers:
Sever21 [200]3 years ago
7 0
2. Transverse
hope this helps : )
IrinaVladis [17]3 years ago
3 0
2) transverse



hope this helped:)
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Sally's displacement (5m forward) is 10m less than her distance traveled (15m).  <em>(B)</em>

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yesenia wants to bake cookies in her electric oven. the oven will transform electrical energy into ________ energy?
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<span>The oven will transform electrical energy into heat energy</span>
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There are initially No nuclei in a radioactive source. After a time interval of three half-lives, what is the number of nuclei t
ladessa [460]

The number of nuclei that have decayed after three half-lives is 12.5% of the original mass.

<h3>What is half live of radioactive isotope?</h3>

The half life of a radioactive isotope is the time taken for the element to decay to half of its original mass.

<h3>Number of nuclei decayed after 3 half lives</h3>

N = N₀/(2³)

N = N₀/8

N = 0.125N₀

N = 12.5% of N₀

where;

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  • N₀ is the original mass

Thus, the number of nuclei that have decayed after three half-lives is 12.5% of the original mass.

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A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr
max2010maxim [7]

Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is  \phi _2  = 1.57 \  rad

Explanation:

From the question we are told that

    The wavelength of the spherical wave is  \lambda =  2.0 \ mm =  \frac{2}{1000} = 0.002 \ m

    The first radius  is  r_1  = 4.0 \ mm  = \frac{4}{1000}  = 0.004 \ m

     The phase at that instant is  \phi _1 = \pi \ rad

     The second radius is  r_2  = 3.5 \ mm  = \frac{3.5}{1000}  = 0.0035 \ m

Generally the phase difference is mathematically represented as

          \Delta  \phi =  \phi _2 -  \phi _1

this can also be expressed as

         \Delta \phi =  \frac{2 \pi }{\lambda } (r_2 - r_1 )

So we have that

   \phi _2 -  \phi _1 =   \frac{2 \pi }{\lambda } (r_2 - r_1 )

substituting values

     \phi _2 -  \pi =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 )

    \phi _2  =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 ) +   3.142

   \phi _2  = 1.57 \  rad

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You are in a car travelling to dinner when a light ahead suddenly turns red.
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