Answer:
0.46km
Explanation:
45963cm/100cm=459.63m/1000m=0.45963 or 0.46km
Can you provide the multiple choices ?
Based on the calculations, the average velocity is equal to 360 m/s and the percent difference is equal to 4.72%.
<h3>What is average velocity?</h3>
An average velocity can be defined as the total distance covered by a physical object divided by the total time taken.
<h3>What is an
average?</h3>
An average is also referred to as mean and it can be defined as a ratio of the sum of the total number in a data set to the frequency of the data set.
<h3>How to calculate the
average velocity?</h3>
Mathematically, the average velocity for this data set would be calculated by using this formula:
Average = [F(v)]/n
Vavg = [v₁ + v₂ + v₃ + v₄ + v₅)/5
Since the values of the average velocity from the table are missing, we would assume the following values for the purpose of an explanation:
Substituting the parameters into the formula, we have:
Vavg = [300 + 450 + 500 + 250 + 300)/5
Vavg = 1800/5
Vavg = 360 m/s.
Next, we would calculate the percent difference by using this formula:
![Percent \;difference = \frac{[V_{avg}\;-\;V_{sound}]}{V_{sound}} \times 100](https://tex.z-dn.net/?f=Percent%20%5C%3Bdifference%20%3D%20%5Cfrac%7B%5BV_%7Bavg%7D%5C%3B-%5C%3BV_%7Bsound%7D%5D%7D%7BV_%7Bsound%7D%7D%20%5Ctimes%20100)
Percent difference = [360 - 343]/360 × 100
Percent difference = 17/360 × 100
Percent difference = 0.0472 × 100
Percent difference = 4.72%.
Read more on average here: brainly.com/question/9550536
#SPJ1
<u>Answer</u>
9 m
<u>Explanation</u>
The energy stored in a spring is given by:
Energy = 1/2 k²e
Where e is the compression and k is the spring constant.
Energy = 1/2 × 176,400 × 0.2²
= 3,528 N
The same energy will then be converted to potential energy given by:
Energy = mgh
Where m is the mass, g is the gravity and h is the height above the ground.
Energy = mgh
3,528 = 40 × 9.8 × h
3,528 = 392h
h = 9 m
Answer: +2.10V
Explanation:

Using Nernst equation :

![E_{cell}=E^o_{cell}-\frac{0.059}{n}\log [Al^{3+}]^2\times [I^-]^6](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.059%7D%7Bn%7D%5Clog%20%5BAl%5E%7B3%2B%7D%5D%5E2%5Ctimes%20%5BI%5E-%5D%5E6)
where,
= standard emf for the cell = +2.20 V
n = number of electrons in oxidation-reduction reaction = 6
= emf of the cell = ?
= concentration = 
= concentration = 
Now put all the given values in the above equation, we get:
![E_{cell}=+2.20-\frac{0.059}{6}\log [5.0\times 10^{-3}]^2\times [0.10]^6](https://tex.z-dn.net/?f=E_%7Bcell%7D%3D%2B2.20-%5Cfrac%7B0.059%7D%7B6%7D%5Clog%20%5B5.0%5Ctimes%2010%5E%7B-3%7D%5D%5E2%5Ctimes%20%5B0.10%5D%5E6)

The standard emf for the cell using the overall cell reaction below is +2.10 V