PLEASE PLS HELP ASAP!!!! WILL MARK BRAINLIEST!!! ANSWER THE QUESTIONS USING THE DIAGRAM!

Chemistry

1 answer:

Yanka [14]3 years ago

7 0

Answer:

In an earthquake, the initial seismic energy wave is called a primary wave. It compresses the material ahead of it; other types of subsequent waves travel in sideways and up-and-down motions. A primary wave travels at different speeds depending on what type of substance it is traveling through. In order to determine how long it will take to travel 2,000 km we have to do the math, using the speed in km/sec and setting up proportions. In a solid such as rock, the primary wave can travel at 5 km/sec; it would take 400 seconds, or about 6.7 minutes to travel 2,000 km. If traveling through water, the wave travels at about 1.45 km/sec and would need 1,379 seconds (23 minutes) to travel 2,000 km. Primary waves traveling through air travel at the speed of sound (.34 km/sec), and would take 5,882 seconds (98 minutes) to travel 2,000 km.

Explanation:

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Use the drop-down menus to select the correct name for each of the organic compounds.

Molodets [167]

Answer:

Here's what I get

Explanation:

CH₃CH₂CH₂CH₂CH₂CH₃ — hexane

CH₂=CHCH₂CH₂CH₂CH₃ — hex-1-ene is the preferred IUPAC name (PIN). 1-Hexene is accepted

CH₃C≡CCH₃ — but-2-yne (PIN); 2-butyne is accepted

CH₃CH(CH₃)CH₂CH₂CH₃ — 2-methylpentane

CH₃CH₂CHCICH₂CH₃ — 3-chloropentane

5 0

3 years ago

Read 2 more answers

When a 5.00-g metal piece, A, was immersed in 38.0 mL of water, the water level rose to 50.0 mL. Similarly, when a 5.00-g metal

Mnenie [13.5K]

Answer:

A is denser than B as it's volume for the same mass is smaller.

Explanation:

Hello.

In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:

$V_A=50.0mL-38.0mL=12.0mL\\\\V_B=60.0mL-38.0mL=22.0mL$

Next, we compute the densities as shown below:

$\rho_A=\frac{m_A}{V_A}=\frac{5.00g}{12.0mL}=0.42g/mL\\ \\\rho_B=\frac{m_B}{V_B}=\frac{5.00g}{22.0mL}=0.23g/mL$

In such a way, A is denser is B as it's volume for the same mass is smaller.

Best regards.

4 0

3 years ago

At-57 °C and 1 atm, carbon dioxide is in which phase? View Available Hint(s) Phase diagrams for water (Figure 1)and carbon dioxi

goblinko [34]

Answer:

Gas

Increase the pressure

Explanation:

Let's refer to the attached phase diagram for CO₂ (not to scale).

At -57 °C and 1 atm, carbon dioxide is in which phase?

If we look at the intersection between -57°C and 1 atm, we can see that CO₂ is in the gas phase.

At 10°C and 2 atm carbon dioxide is in the gas phase. From these conditions, how could the gaseous CO₂ be converted into liquid CO₂?

Since at 10°C and 2 atm carbon dioxide is below the triple point, the only way to convert it into liquid is by increasing the pressure (moving up in the vertical direction).