What is Cd2+ and F1- together as a formula

Chemistry

1 answer:

geniusboy [140]3 years ago

4 0

Answer:

i am not sure tho

Explanation:

Cd ²+ + F¹- = CdF2

F fluor is a non metal so he takes the electons that Cd gives so if Vd has to give 2 electrons and F can take only 1, there has to be 2 F atoms so all the electrona can be neutral and in ionisation

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Which of the following would shift the following equilibrium system to the right? C2H2(g) + H2O(g) ⇌ CH3CHO(g) Removing H2O(g) f

Leni [432]

<h2>Answer:</h2>

The right choice is Adding H2O(g) to the system

<h2>Explanation:</h2>

If we dilute a solution by adding solvent like water, all of the concentrations will decrease and a change in Q occurs. If there are more species in solution that are products than reactants then Q will decrease. Hence the reaction will then shift towards the right side which is product side to reach equilibrium because there will be an increase the concentration of the reactants side,

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tigry1 [53]

Not always ammonium salts of weak acids form neutral solutions.

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As was already established, formate is a weak base and will create hydroxide ions in water, whereas ammonium is a weak acid and will make hydronium ions in water.

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Since the acid ionization of NH4+ is more favored than the base ionization of HCO2-, the solution will be acidic.

To learn more about ammonium salts:

brainly.com/question/10874844

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2 years ago

How can an atom create charge

irga5000 [103]

Answer:

When the electrons hit the atoms in the chamber, they cause some of the electrons in the atoms to be stripped or knocked away. ... When one or more electrons is knocked off of an atom, it becomes positively charged. It is now an positive ion. A negative ion can be made by adding an electron to an atom.

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3 years ago

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In a undisturbed layer, how do we know which layer was deposited first ?

OLEGan [10]

Answer:

It's the bottom layer.

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Scientists use the Law of Superposition to determine the relative age of a layer of sedimentary rock:

The oldest rock layer is at the bottom of an undisturbed bed.

Thus, Layer A in the figure below was deposited first.