Answer: The average atomic mass of this element is 131.5 amu
Explanation:
Mass of isotope 1 = 131.90 amu
% abundance of isotope 1 = 90% = 
Mass of isotope 2 = 127.90 amu
% abundance of isotope 2 = 10% = 
Formula used for average atomic mass of an element :

![A=\sum[(131.90\times 0.9)+(127.90\times 0.1)]=131.5amu](https://tex.z-dn.net/?f=A%3D%5Csum%5B%28131.90%5Ctimes%200.9%29%2B%28127.90%5Ctimes%200.1%29%5D%3D131.5amu)
The average atomic mass of this element is 131.5 amu
Answer: potential energy into kinetic energy through sound
Explanation:
Basically, this problem asks you to convert units of volume from cm³ to μL. Cubic centimeters is the cubic volume equivalent of milliliters or mL. According to the metric system for L, microliter is 10⁻⁶ of a liter, while milliliter is 10⁻³ of a liter. Therefore, the solution is written as
(1.12×10⁻²³ cm³)*(1 mL/1 cm³)*(10⁻³ L/ 1 mL)*(1μL/10⁻⁶ L) = 1.12×10⁻²⁰ μL
The percent yield of carbon dioxide will be 49.0 %.
<h3>Percent yield</h3>
First, let's look at the equation of the reaction:

The mole ratio of octane to oxygen is 2:25.
Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol
Mole of 19.1 g oxygen = 19.1/32 = 0.60 mol
Thus, octane is limiting.
Mole ratio of octane to carbon dioxide = 2:16.
Equivalent mole of carbon dioxide = 0.03 x 8 = 0.24 mol
Mass of 0.24 mol carbon dioxide = 0.24 x 44.01 = 10.5624 grams
Percent yield of carbon dioxide = 5.18/10.5624 = 49.0 %
More on percent yield can be found here: brainly.com/question/17042787
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