Assuming that the question is about making glucose, then you need to know the equation for the reaction. The equation should be:
C6H12O6<span>(s) + 6O2(g) -->6CO2(g) + 6H2O(g)
In this equation, 6 molecules of CO2 would react with 6 molecules of H2O which mean it has 1:1 ratio. The molecular weight for CO2 should be 44g/mole and H2O is 18g/mole. Then the calculation would be: 6/6 * (157.35g/44g) * 18g= 64.37g</span>
ANSWER: C. Simple machine
Answer:
I think the answer is X if wrong i´m sorry
Explanation:
Answer:
Vol of 4 moles CO₂(g) at STP = 89.6 Liters
Explanation:
STP
P = 1 Atm
V =
T = 0°C = 273 K
n = 4 moles
R = 0.08206 L·Atm/mol·K
Using Ideal Gas Law PV = nRT => V = nRT/P
V = (4 moles)(0.08206 L·Atm/mol·K)(273 K)/(1 Atm) = 89.6 Liters
They will mold into different shapes